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nata0808 [166]
3 years ago
14

An urn contains 100 marbles. Fifty are purple, ten are green, fifteen are red, and twenty five are orange. Two marbles are drawn

at random one after another with replacement. Calculate each probability. a. P(purple and orange) b) P(green and green)
Mathematics
2 answers:
yarga [219]3 years ago
8 0

Answer:

A- 1/2 and 1/4 (or together is 75%)  B- 1/10 and 1/10

Step-by-step explanation:

50 purple

10 green

15 red

25 orange

Total = 100

Over [174]3 years ago
7 0
To find A you would first take the 50 purple and 25 orange and combine them, this would give you 75 you would then put that over a 100 since there’s a 100 marbles total so 75/100=.75 which is 75% you would do the same for the green 10/100=.1 so a) 75% and b).1% or 10%
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Answer:

a)P=0.42

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Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}

a) we have k=2, n=10 and p=0.01:

P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42

b) We have, 1-(1-p)^n=P, Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.

1-0.99^n\geq 0.95\\0.99^n\leq 1-0.95\\0.99^n\leq 0.05\\n\geq 297

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Answer:

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