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LiRa [457]
3 years ago
11

Describe software as a service. what features distinguish it from application software installed on a personal computing device

Computers and Technology
2 answers:
LekaFEV [45]3 years ago
7 0

Answer:

Any modern computer has a variety of softwares that do many tasks.

They can be classified into two broad categories:

• System software that included the firmware (The personal computer BIOS, for example), device drivers, the operating system, and typically a graphical interface that together allow the user to interact with the computer and its peripherals.

• Service software, which allows the user to do one or more specific tasks. Applications can have a wide range of use, often worldwide; In these cases, the programs tend to be more robust and more standardized. Programs written for a small market have a lower level of standardization.

Triss [41]3 years ago
6 0
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Translate the following MIPS code to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3
Romashka [77]

Answer:

f = 2 * (&A[0])

See explaination for the details.

Explanation:

The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:

The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.

Explanation:

If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.

C statement:

$t0 = $s6 + 4

$t0 = &A[1]

The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.

Explanation:

Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.

C statement:

$t1 = $s6 + $0

$t1 = $s6

$t1 = &A[0]

The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).

Explanation:

The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].

C statement:

($t0 + 0) = A[1]

A[1] = $t1

A[1] = &A[0]

The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.

Explanation:

The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.

C statement:

$t0 = ($t0 + 0)

$t0 = A[1]

$t0 = &A[0]

The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.

Explanation:

The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.

C statement:

$s0 = $t1 + $t0

$s0 = &A[0] + &A[0]

f = 2 * (&A[0])

The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.

3 0
3 years ago
People who are reading this:
Gnom [1K]

Answer:

Awe thanks hun!

Explanation:

3 0
2 years ago
Read 2 more answers
What is a computer system?
klio [65]
A system of interconnected computers that share a central storage system and various peripheral devices such as a printers, scanners, or routers. Each computer connected to the system can operate independently, but has the ability to communicate with other external devices and computers

<span>Read more: http://www.businessdictionary.com/definition/computer-system.html</span>
4 0
3 years ago
Which statement best justifies the use of a high-speed cache in a CPU?
crimeas [40]

Cache memory is a high-speed memory that stores the instructions and data that have been frequently accessed.  It decreases the time it takes to decode the instructions stored in the instruction pipeline.

A.  It decreases the time it takes to decode instructions stored in the instruction pipeline.

<u>Explanation:</u>

Whenever an instruction is invoked or some data is accessed, the CPU looks for it in the cache memory before accessing the main memory.

If the content is found in the cache memory, it accessed from there and then and hence the access time and decode time is reduced as there were no main memory lockups.

6 0
3 years ago
What is sytem software?
schepotkina [342]

Answer:

system software is the set of computer programs that controls and manage the operations of computer hardware.

7 0
1 year ago
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