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Alex777 [14]
3 years ago
5

The picture that graphically represents the items you use in windows is called a/an

Computers and Technology
1 answer:
rodikova [14]3 years ago
3 0
The picture that graphically represents the times you use in windows is called an icon ( this is true for windows 7, assuming that was what you were referring to. I am not familiar with windows 8)
You might be interested in
Try using the inv command to find the inverse of the matrix Notice the strange output. Include your command and the output in yo
denpristay [2]

Answer:

a)

inv([1 1; 100 100])

warning: matrix singular to machine precision

warning: called from ATest at line 1 column1

ans =

Inf Intf

Inf Inf

b)

A = [4, 9; 5, 11]

B = inv(A)

A*B

B*A

4. 9

5 11

-11.0000 9.0000

5.0000 4.0000

ans . 00000 -0.00000

0 . 00000 1.00000

ans 1.00000 0.00000

0.00000 1.00000

c)

x = [5; 10]

y = A*x

x = [5; 10]

y=

110 135"

d)

B * y is

5.0000

10.0000

e)

B * y

ans 5.0000

10.0000

3 0
3 years ago
A. Calculate the diffusion coefficient for magnesium in aluminum at 450°C.
SIZIF [17.4K]

Answer:

a) D = 4.88 * 10^(-14) m^2 / s

b)   <em>t </em>= 1.1 hr

Solution:

a) Magnesium in Aluminum diffusion:

D = Do * exp(-Qd / RT)

  =  (1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15)

  = 4.88 * 10^(-14) m^2 / s

D = 4.88 * 10^(-14) m^2 / s

b) The composition remains same at say the distance Xo:

(Cx - Co) / (Cs - Co) = Constant

Xo^2 / D_{550} * <em>t </em>= Xo^2 / D_{450} * 15

D_{550} * <em>t </em>= D_{450} * 15

(1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15) * <em>t</em>

(4.88 * 10^(-14) m^2 / s) * 15

by, solving for <em>t </em>we get:

 <em>t </em>= 1.1 hr

So, the time required is 1.1 hr.

5 0
2 years ago
On what menu in Microsoft Word can you locate the Macro feature?
Harrizon [31]

Answer:

View

Explanation:

Microsoft Word refers to a word processing software application or program developed by Microsoft Inc. to enable its users type, format and save text-based documents.

In Microsoft Word 2019, the users are availed with the ability to edit the word document in the following view type;

I. View Mode

II. Print Mode

III. Drift Layout

The Microsoft Word developers has made it easy for their users to automate the tasks used frequently through the creation and execution of macros.

Basically, macros comprises of commands and instructions which may be grouped together as a single command to automatically execute a task. You can locate the Macro feature in the View tab of Microsoft Word.

6 0
3 years ago
Create a TicTacToe class that initializes a 3x3 board of "-" values. We will use this class in future exercises to fully build o
kap26 [50]

Answer:

public class TicTacToe //Defining TicTacToe class

{

char board[3][3] ; //Creating a 2D array instance variable

TicTacToe() //Constructor to initialize the array with " - "

{

for( int i = 0;i<3;i++) //Loop for the row of array

{

for(int j = 0;j<3;j++) //Loop for the column of array

{

Board[i][j] = '-'; //Assigning "-" in each cell

}

}

}

public char getter() //Defining getter() method to return the array

{

return Board; //returning the array

}

}

8 0
3 years ago
Develop a C program that calculates the final score and the average score for a student from his/her (1)class participation, (2)
Ghella [55]

Answer:

#include <iomanip>

#include<iostream>

using namespace std;

int main(){

char name[100];

float classp, test, assgn, exam, prctscore,ave;

cout<<"Student Name: ";

cin.getline(name,100);

cout<<"Class Participation: "; cin>>classp;

while(classp <0 || classp > 100){  cout<<"Class Participation: "; cin>>classp; }

cout<<"Test: "; cin>>test;

while(test <0 || test > 100){  cout<<"Test: "; cin>>test; }

cout<<"Assignment: "; cin>>assgn;

while(assgn <0 || assgn > 100){  cout<<"Assignment: "; cin>>assgn; }

cout<<"Examination: "; cin>>exam;

while(exam <0 || exam > 100){  cout<<"Examination: "; cin>>exam; }

cout<<"Practice Score: "; cin>>prctscore;

while(prctscore <0 || prctscore > 100){  cout<<"Practice Score: "; cin>>prctscore; }

ave = (int)(classp + test + assgn + exam + prctscore)/5;

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;  

return 0;}

Explanation:

The required parameters such as cin, cout, etc. implies that the program is to be written in C++ (not C).

So, I answered the program using C++.

Line by line explanation is as follows;

This declares name as character of maximum size of 100 characters

char name[100];

This declares the grading items as float

float classp, test, assgn, exam, prctscore,ave;

This prompts the user for student name

cout<<"Student Name: ";

This gets the student name using getline

cin.getline(name,100);

This prompts the user for class participation. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Class Participation: "; cin>>classp; </em>

<em> while(classp <0 || classp > 100){  cout<<"Class Participation: "; cin>>classp; } </em>

This prompts the user for test. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Test: "; cin>>test; </em>

<em> while(test <0 || test > 100){  cout<<"Test: "; cin>>test; } </em>

This prompts the user for assignment. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Assignment: "; cin>>assgn; </em>

<em> while(assgn <0 || assgn > 100){  cout<<"Assignment: "; cin>>assgn; } </em>

This prompts the user for examination. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Examination: "; cin>>exam; </em>

<em> while(exam <0 || exam > 100){  cout<<"Examination: "; cin>>exam; } </em>

This prompts the user for practice score. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

<em> cout<<"Practice Score: "; cin>>prctscore; </em>

<em> while(prctscore <0 || prctscore > 100){  cout<<"Practice Score: "; cin>>prctscore; } </em>

This calculates the average of the grading items

ave = (int)(classp + test + assgn + exam + prctscore)/5;

This prints the calculated average

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;  

8 0
3 years ago
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