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4 years ago

12

How can you rewrite the expression (8-5i)^2 in the form a+bi?

2 answers:

otez555 [7]4 years ago

8 0

(a-b)^2 = a^2-2ab+b^2

(8-5i)^2 = 8^2-2(8)(5i)+(5i)^2

= 64-80i+25i^2

i^2=-1

So

= 64-80i+25(-1)

=64-25-80i

= <em><u>39 - 80i</u></em>

which is your answer :)

Natalija [7]4 years ago

8 0

(8 - 5i)²
(8 - 5i)(8 - 5i)
64 - 40i - 40i + 25i²
64 - 80i + 25i²
64 - 80i + 25(-1)
64 - 25 - 80i
39 - 80i

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Answer:

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Step-by-step explanation:

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3 years ago

Simplify (-32) ÷ (-4)

Keith_Richards [23]

$\bold{Hey\ there!}$

$\bold{Guide\downarrow}$

$\bold{Negative}$ & $\bold{Negative}$ = $\bold{Positive}$

$\bold{Positive}$ & $\bold{Negative}$ = $\bold{Negative}$

$\bold{Positive}$ & $\bold{Positive}$ = $\bold{Positive}$

$\bold{Negative}$ & $\bold{Positive}$ = $\bold{Negative}$

$\bold{(-32)\div(-4)}$

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$\text{Good luck on your assignment and enjoy your day!}$

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WARRIOR [948]

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Step-by-step explanation:

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