How can you rewrite the expression (8-5i)^2 in the form a+bi?
2 answers:
(a-b)^2 = a^2-2ab+b^2
(8-5i)^2 = 8^2-2(8)(5i)+(5i)^2
= 64-80i+25i^2
i^2=-1
So
= 64-80i+25(-1)
=64-25-80i
= <em><u>39 - 80i</u></em>
which is your answer :)
(8 - 5i)²
(8 - 5i)(8 - 5i)
64 - 40i - 40i + 25i²
64 - 80i + 25i²
64 - 80i + 25(-1)
64 - 25 - 80i
39 - 80i
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