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3 years ago

12, 13, 15, 15, 16, 19,19,19,20,21,25 what is the median?

2 answers:

8 0

Median - the middle of a data set

12 , 13 , 15 , 15 , 16 , 19 , 19 , 19 , 20 , 21 , 25
x x x x x x x x x x

The median is 19

Mark brainliest if this helped :D

Olin [163]3 years ago

4 0

The median is the middle number.

The middle number is 19.

Median = 19.

Hope this helped.

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1/2 3/4 1/2 a. 5/8 b. 5/4 c.1 3/4 d. 1 7/4

Sever21 [200]

I think the correct answer would be C. hope this helped !

8 0

2 years ago

Read 2 more answers

T-5 >3(-2+t) please help me

Vladimir79 [104]

Answer:

t < 1/2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form: t < 1/2

Interval Notation: ( -infinity, 1/2)

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2 years ago

Maryam made a fruit salad with 1 pound of melon and 8 2/5 pounds of berries. How many pounds of fruit did Maryam use in all?

____ [38]

Answer:

9 2/5 lb

Step-by-step explanation:

Both melon and berries are "fruits."

The total weight of the fruit used is thus 1 lb + 8 2/5 lb, or 9 2/5 lb.

6 0

3 years ago

The curve with equation y=e^2x/4+3e^x has one stationary point.find the exact value of the coordinates of this point

Softa [21]

$y=\dfrac{e^{2x}}{4+3e^x}$
$\implies y'=\dfrac{2e^{2x}(4+3e^x)-3e^xe^{2x}}{(4+3e^x)^2}$
$\implies y'=\dfrac{8e^{2x}+3e^{3x}}{(4+3e^x)^2}$

Stationary points occur where the derivative is zero. The denominator is positive for all $x$ , so we only need to worry about the numerator.

$8e^{2x}+3e^{3x}=e^{2x}(8+3e^x)=0$

$e^{2x}>0$ for all $x$ , so we can divide through:

$8+3e^x=0\implies e^x=-\dfrac83$

But $e^x>0$ for all $x\in\mathbb R$ , so this function has no stationary points...

I suspect there may be a typo in the question.

6 0

2 years ago

I need to know the perimeter because i can't figure out some of the side lengths.

blsea [12.9K]

The primeter is the outside p=2+2 +3+1+1 so the primiter is 9

3 0

2 years ago