Answer:
a) e probability that a randomly selected baseball has a weight greater than 5.14 ounces
=P(X>5.14) =(b-x)/(b-a) =(5.155-5.14)/(5.155-5.085)=0.2143
b)
probability that a randomly selected baseball has a circumference less than 9.03 inches
=P(X<9.03) =(x-a)/(b-a) =(9.03-9)/(9.1-9)=0.3
c) probability that a randomly selected baseball will have a weight between 5.11 and 5.13 ounces and a circumference between 9.04 and 9.06 inches
=((5.13-5.11)/(5.155-5.085))*((9.06-9.04)/(9.1-9.0))=0.0571
Answer:
You can conclude from the diagram that m∠P is less than m∠N ⇒ A
Step-by-step explanation:
- In any triangle, you can arrange the lengths of the sides according to the measure of the opposite angles
- In any triangle, you can arrange the measure of the angles according to the lengths of the opposite sides
<u><em>Example:</em></u>
In ΔABC, if the arrangement of the sides is AB < BC < CA, then the arrangement of the measures of the angles is m∠C < m∠A < m∠B
Let us use this fact to solve the question
→ In ΔKNP
∵ KP = 8 units
∵ KN = 6 units
∵ 6 < 8
∴ KN < KP
∵ ∠P is opposite to the side KN
∵ ∠N is opposite to the side KP
∵ KN < KP
→ By using the fact above
∴ m∠P < m∠N
∴ m∠P is less than m∠N
∴ You can conclude from the diagram that m∠P is less than m∠N
Is there anything else on the paper that can help me with that? like any questions at the top?
14 books in 3 months is 35%
all of books is 100%
14- 35%
x- 100%
we calculate from proportions, crosswise:
Answer: Benito sign up to read 40 books.
Greetings,
n00nst00p :)
