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mamaluj [8]
3 years ago
10

Relationship between

Physics
2 answers:
vlabodo [156]3 years ago
5 0

Answer:

The energy of a wave is proportional to the square of its amplitude

Explanation:

The graph in this problem is missing.

However, we can describe what is the relationship between amplitude and energy of a wave.

In fact, for a wave, the energy carried by it is proportional to the square of its amplitude:

E\propto A^2

where

E is the energy of the wave

A is the amplitude

This means that, for instance:

- as the amplitude of the wave increases by a factor of 2, the energy carried by the wave increases by a factor of 4

- As the amplitude of the wave increases by a factor of 3, the energy carried by the wave increases by a factor of 9

... and so on.

QveST [7]3 years ago
4 0

Answer:

No, it is not correct because as the amplitude of a wave increases, the energy it carries also increases. This graph shows that as the amplitude increases, the energy decreases.

Explanation:

i got it wrong :(

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The achievement of lifting a rocket off the ground and into space can be explained by
lawyer [7]

Answer:

The achievement of lifting a rocket off the ground and into space can be explained by Newton's third law of motion. What is required for a rocket to lift off into space? Thrust is required for a rocket to lift off into space, ... An object that travels around another object in space is called a satellite.

Explanation:

4 0
3 years ago
How much power is required to lift a 60 kg bed to the top of a 3 meter flight of stairs in 10 seconds?
Zigmanuir [339]

Answer:

176.58Watts

Explanation:

Power= work done /time

Where mass(m)=60kg

Height (h) =3m

Time(s)=10s

Force of gravity = 9.81m/s^2

Power=mgh/t

Power= (60kg) * (9.81m/s^2) * (3m)/10s

Power= 176.58Watts

8 0
4 years ago
A sailor pulls a crate across the deck of a ship with a rope, exerting a horizontal force of 150. N. The crate, which has a mass
nata0808 [166]

Answer:

B

Explanation:

7 0
3 years ago
6. A 2-kg ball B is traveling around in a circle of radius r1 = 1 m with a speed (vB)1 = 2 m/s. If the attached cord is pulled d
kipiarov [429]

Answer:

Explanation:

Given that,

Mass of ball m = 2kg

Ball traveling a radius of r1= 1m.

Speed of ball is Vb = 2m/s

Attached cord pulled down at a speed of Vr = 0.5m/s

Final speed V = 4m/s

Let find the transverse component of the final speed using

V² = Vr²+ Vθ²

4² = 0.5² + Vθ²

Vθ² = 4²—0.5²

Vθ² = 15.75

Vθ =√15.75

Vθ = 3.97 m/s.

Using the conservation of angular momentum,

(HA)1 = (HA)2

Mb • Vb • r1 = Mb • Vθ • r2

Mb cancels out

Vb • r1 = Vθ • r2

2 × 1 = 3.97 × r2

r2 = 2/3.97

r2 = 0.504m

The distance r2 to the hole for the ball to reach a maximum speed of 4m/s is 0.504m

The required time,

Using equation of motion

V = ∆r/t

Then,

t = ∆r/Vr

t = (r1—r2) / Vr

t = (1—0.504) / 0.5

t = 0.496/0.5

t = 0.992 second

7 0
3 years ago
Can someone help me with this real quick?
ch4aika [34]

Answer:

7,546 J

Explanation:

recall that Potential energy is given by

P.E = mgΔh

where m = 70kg (given)

g = 9.8 m/s² (acceleration due to gravity)

Δh = change in height

= distance from top of building to top of car

= height of building - height of car

= (5+8) - 2

= 11m

substituting all these into the equation:

P.E = mgΔh

= 70 x 9.8 x 11

= 7,546 J

4 0
3 years ago
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