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3 years ago

Relationship between

Physics

2 answers:

vlabodo [156]3 years ago

5 0

Answer:

The energy of a wave is proportional to the square of its amplitude

Explanation:

The graph in this problem is missing.

However, we can describe what is the relationship between amplitude and energy of a wave.

In fact, for a wave, the energy carried by it is proportional to the square of its amplitude:

$E\propto A^2$

where

E is the energy of the wave

A is the amplitude

This means that, for instance:

- as the amplitude of the wave increases by a factor of 2, the energy carried by the wave increases by a factor of 4

- As the amplitude of the wave increases by a factor of 3, the energy carried by the wave increases by a factor of 9

... and so on.

QveST [7]3 years ago

4 0

Answer:

No, it is not correct because as the amplitude of a wave increases, the energy it carries also increases. This graph shows that as the amplitude increases, the energy decreases.

Explanation:

i got it wrong :(

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The Tevatron acceleator at the Fermi National Accelerator Laboratory (Fermilab) outside Chicago boosts protons to 1 TeV (1000 Ge

Eva8 [605]

Answer:

a) $v = c \cdot 0.04 = 1.2\cdot 10^{7} m/s$

b) $v = c \cdot 0.71 = 2.1\cdot 10^{8} m/s$

c) $v = c \cdot 0.994 = 2.97\cdot 10^{8} m/s$

d) $v = c \cdot 0.999 = 2.997\cdot 10^{8} m/s$

e) $v = c \cdot 0.9999 = 2.999\cdot 10^{8} m/s$

Explanation:

At that energies, the speed of proton is in the relativistic theory field, so we need to use the relativistic kinetic energy equation.

$KE=mc^{2}(\gamma -1) = mc^{2}(\frac{1}{\sqrt{1-\beta^{2}}} -1)$ (1)

Here β = v/c, when v is the speed of the particle and c is the speed of light in vacuum.

Let's solve (1) for β.

$\beta = \sqrt{1-\frac{1}{\left (\frac{KE}{mc^{2}}+1 \right )^{2}}}$

We can write the mass of a proton in MeV/c².

$m_{p}=938.28 MeV/c^{2}$

Now we can calculate the speed in each stage.

a) Cockcroft-Walton (750 keV)

$\beta = \sqrt{1-\frac{1}{\left (\frac{0.75 MeV}{938.28 MeV}+1 \right )^{2}}}$

$\beta = 0.04$

$v = c \cdot 0.04 = 1.2\cdot 10^{7} m/s$

b) Linac (400 MeV)

$\beta = \sqrt{1-\frac{1}{\left (\frac{400 MeV}{938.28 MeV}+1 \right )^{2}}}$

$\beta = 0.71$

$v = c \cdot 0.71 = 2.1\cdot 10^{8} m/s$

c) Booster (8 GeV)

$\beta = \sqrt{1-\frac{1}{\left (\frac{8000 MeV}{938.28 MeV}+1 \right )^{2}}}$

$\beta = 0.994$

$v = c \cdot 0.994 = 2.97\cdot 10^{8} m/s$

d) Main ring or injector (150 Gev)

$\beta = \sqrt{1-\frac{1}{\left (\frac{150000 MeV}{938.28 MeV}+1 \right )^{2}}}$

$\beta = 0.999$

$v = c \cdot 0.999 = 2.997\cdot 10^{8} m/s$

e) Tevatron (1 TeV)

$\beta = \sqrt{1-\frac{1}{\left (\frac{1000000 MeV}{938.28 MeV}+1 \right )^{2}}}$

$\beta = 0.9999$

$v = c \cdot 0.9999 = 2.999\cdot 10^{8} m/s$

Have a nice day!

4 0

4 years ago

WILL GIVE BRAINLIEST

Diano4ka-milaya [45]

Answer:

nice to help you

Explanation:

If for any reason the Sun shrank smaller than the Earth, this shrunken Sun wouldn't have the mass to create fusion and would burn out completely. Our solar system would lose its only star. ... Earth's mass would be at least 333,000 times bigger than it is now. Imagine the gravity that planet would have.

5 0

3 years ago

The frequency of the sound waves produced by a string _____.

Gnoma [55]

increases as the tension of the string increases

7 0

3 years ago

Read 2 more answers

During the spin cycle of your clothes washer, the tub rotates at a steady angular velocity of 31.7 rad/s. Find the angular displ

Crank

Answer:

$\Delta \theta = 3116.11\,rad$ and $\Delta \theta = 495.944\,rev$

Explanation:

The tub rotates at constant speed and the kinematic formula to describe the change in angular displacement ( $\Delta \theta$ ), measured in radians, is:

$\Delta \theta = \omega \cdot \Delta t$

Where:

$\omega$ - Steady angular speed, measured in radians per second.

$\Delta t$ - Time, measured in seconds.

If $\omega = 31.7\,\frac{rad}{s}$ and $\Delta t = 98.3\,s$ , then:

$\Delta \theta = \left(31.7\,\frac{rad}{s} \right)\cdot (98.3\,s)$

$\Delta \theta = 3116.11\,rad$

The change in angular displacement, measured in revolutions, is given by the following expression:

$\Delta \theta = (3116.11\,rad)\cdot \left(\frac{1}{2\pi} \frac{rev}{rad} \right)$

$\Delta \theta = 495.944\,rev$

6 0

3 years ago

If a textbook weighs 19.6 Newtons on Venus what is the acceleration of gravity on Venus

laila [671]

We can't tell from the information in the question.

Weight = (mass) x (acceleration of gravity).

In order to find any of those quantities, we need to know
the other TWO things.

We can't answer the question until we know either the mass
of the book, or its weight on some other planet other than Venus.

6 0

3 years ago