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White raven [17]
3 years ago
9

Question 13 (1 point)

Physics
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer:

Reflective clothing. So vehicles can see them and stuff.

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How does reducing the volume of a gas affect its pressure if the temperature of the gas and the number of particles are constant
Tema [17]

have no idea but I think the particles would be affected because they would move faster then normal and have the space to

5 0
3 years ago
An object has kinetic energy of 1500 J and a speed of 120 m/s. What is the mass?
Pie

Explanation:

K.E = 1/2mv²

m = 2K.E/v²

m = 2 x 1500/(120)²

m = 3000/14400

m = 0.208 kg

3 0
3 years ago
.In real life, a given system can approach equilibrium from different starting points but will still have the same equilibrium c
Degger [83]
<span>It does not matter where the system starts but it will reach to an equilibrium state when the equilibrium ratio is reached.

hope it helps </span>
5 0
3 years ago
In this week's experiment, you send an unpolarized light beam through two polarizers in series. You orient the first polarizer s
g100num [7]

Answer:

Part a)

\theta = 90 degree

so the polarization axis of two polarizers must be at 90 degree

Part b)

\theta = 20 + 14.3 = 34.3 degree

(vi) set the second polarizer so that its angular scale reads 34.3 degrees.

Explanation:

Part 1)

As per law of Malus we know that the intensity of light coming from the second polarizer and the intensity of the light from first polarizer is related as

I = I_o cos^2\theta

now we know that we rotate the second polarizer till the intensity of the light becomes zero

so we will have

I = 0

so we will have

\theta = 90 degree

so the polarization axis of two polarizers must be at 90 degree

Part b)

when two axis are inclined at 90 degree then scale reads 104.3 degree

so here the scale exceeds the reading by

\Delta \theta = 104.3 - 90 = 14.3

so in order to make them inclined at 20 degree we will have

\theta = 20 + 14.3 = 34.3 degree

(vi) set the second polarizer so that its angular scale reads 34.3 degrees.

7 0
4 years ago
While the change in blank will remain the same during a collision, the force needed to bring an object to a stop can be blank if
Ahat [919]

Explanation :

There are two types of collision i.e. elastic and elastic collision.

  • Elastic collision : In this type of collision, the total momentum and the kinetic energy of the particles remains constant.
  • Inelastic collision : In this type of collision, only the momentum remains constant while there is some loss of kinetic energy occurs.

From Newton's second law,

F = m a

a is the rate of change of velocity.

F=m\dfrac{v}{t}

There is a inverse relation between the force and the time of collision.

The change in <em><u>momentum</u></em> will remain the same during a collision, the force needed to bring an object to a stop can be <em><u>increased</u></em> if the time of the collision is <u><em>decreased</em></u>.

6 0
3 years ago
Read 2 more answers
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