Question 13 (1 point)

Physics

1 answer:

KonstantinChe [14]2 years ago

3 0

Answer:

Reflective clothing. So vehicles can see them and stuff.

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A basketball has a coefficient of restitution of 0.821 in collisions with the wood floor of a basketball court. The ball is drop

Tanya [424]

Answer: The height of its fourth bounce = 0.43m

Explanation:

The coefficient of restitution denoted by (e), is the ratio that shows the final velocity to initial relative velocity between two objects after collision

IT is given by the formula in terms of height as

Coefficient of Restitution, e = √(2gh))/√(2gH) = √(h/H)

Where

Coefficient of Restitution, e= 0.821

H = 2.07 m

At fourth bounce , we have that

Coefficient of Restitution, e⁴ =√(h₄/H)

Putting the given values and solving , we have,

e⁴ =√(h₄/H)

= 0.821⁴ = √(h₄/2.07)

(0.821⁴ )² =h₄/2.07

0.2064 x 2.07 = 0.427 = 0.43

At fourth bounce, h₄ height = 0.43m

7 0

3 years ago

What happens to the orbit time as the distance increases.

Maslowich

The orbital period increases if the orbital distance is increased.

6 0

2 years ago

A 91.5 kg football player running east at 2.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft

matrenka [14]

Answer:

The velocity of the players will be 2.88 m/s in the east direction.

Explanation:

Let 'v' be the velocity of the players after collision.

Consider the east direction as positive direction.

Given:

Mass of the first player is, $m_1 = 91.5$ kg

Initial velocity of the first player is, $u_1 = 2.73$ m/s

Mass of the second player is, $m_2 = 63.5$ kg

Initial velocity of the second player is, $u_2 = 3.09$ m/s

In order to solve this problem we use the law of conservation of momentum which says that the total momentum must be conserved before and after the collision. So we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1 + m_2)v$