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PIT_PIT [208]
3 years ago
6

A robot that can move a hand left and right and rotate the hand 360º is said to have

Physics
1 answer:
Luda [366]3 years ago
3 0

You've described two (2) axes of motion.
The third one would have been up-and-down.
 
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A skater extends her arms, holding a 2 kg mass in each hand. She is rotating about a vertical axis at a given rate. She brings h
Usimov [2.4K]

Explanation:

It is known that relation between torque and angular acceleration is as follows.

                    \tau = I \times \alpha

and,       I = \sum mr^{2}

So,      I_{1} = 2 kg \times (1 m)^{2} + 2 kg \times (1 m)^{2}

                       = 4 kg m^{2}

      \tau_{1} = 4 kg m^{2} \times \alpha_{1}

     \tau_{2} = I_{2} \alpha_{2}

So,      I_{2} = 2 kg \times (0.5 m)^{2} + 2 kg \times (0.5 m)^{2}

                     = 1 kg m^{2}

 as \tau_{2} = I_{2} \alpha_{2}

                   = 1 kg m^{2} \times \alpha_{2}        

Hence,     \tau_{1} = \tau_{2}

                  4 \alpha_{1} = \alpha_{2}

            \alpha_{1} = \frac{1}{4} \alpha_{2}

Thus, we can conclude that the new rotation is \frac{1}{4} times that of the first rotation rate.

8 0
3 years ago
How old are spiral galaxies?<br> I WILL MAKE YOU BRAINLIEST, 5 STARS, AND THANKS! PLEASE ASAP
kondor19780726 [428]

Answer:

Hi there!

The answer is eleven billion years old.

7 0
3 years ago
Read 2 more answers
A cyclist maintains a constant velocity of 6.7 m/s headed away from point
JulsSmile [24]
His position x = V* t = 6.7*56= 375.2 m from point a
3 0
3 years ago
Near Earth, the density of protons in the solar wind (a stream of particles from the Sun) is 12.5 cm-3, and their speed is 564 k
morpeh [17]

Answer:

A) 11.28 x 10^(7) A.m²

B) 2.258 x 10^(17)A

Explanation:

A) The current density is given by the formula ;

J = nqv

Where n is the density of protons in the solar wind which is 12.5 cm³ or 12.5 x 10^(-6) m³

q is the proton charge which is 1.6 x 10^(-19) C

v is velocity which is 564km or 564000m

Thus, J = 12.5 x 10^(-6) x 1.6 x 10^(-19) x 564000 = 11.28 x 10^(7) A.m²

B) the formula for the total current the earth received is given as;

I = JA

The effective area is the cross section of the earth and thus,

Area = πr² where r is the radius of the earth given as: 6.371 x 10^(6)

A = π(6.371 x 10^(6)) ²

So I = 11.28 x 10^(7) x π(6.371 x 10^(6))² = 2.258 x 10^(17)A

7 0
3 years ago
Allison needs to graph the yearly average snowfall in Alaska. She should use a:
Furkat [3]
Answer:

a. bar graph

:D
6 0
3 years ago
Read 2 more answers
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