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Yuri [45]
3 years ago
7

The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is the greatest possible v

alue for the width? Write an inequality to model the problem.
A. 2w + 2 • (3w) ≥112
B. 2w + 2 • (3w) < 112
C. 2w + 2 • (3w) > 112
D. 2w + 2 • (3w) ≤112


Question 2.2. The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible value for the width?
A. 40 cm
B. 19.2 cm
C. 16 cm
D. 8 cm

Mathematics
2 answers:
andre [41]3 years ago
7 0
Q2. The answer is <span>D. 2w + 2 • (3w) ≤112
</span>
The perimeter of a rectangle is: P = 2w + 2l         (w - weight, l - length)
<span>
The perimeter is at most 112 centimeters: P </span>≤ 112
<span>The length of a rectangle is three times its width: l = 3w

</span>P ≤ 112
2w + 2l ≤ 112

l = 3w
2w + 2 * (3w) ≤ 112



Q2.2. The answer is <span>D. 8 cm
</span>
The perimeter of a rectangle is: P = 2w + 2l         (w - weight, l - length)

<span>The length of a rectangle is five times its width: l = 5w
</span><span>The perimeter is at most 96 centimeters: P </span>≤ 96

P ≤ 96
2w + 2l ≤ 96

l = 5w
2w + 2 * 5w ≤ 96
2w + 10w ≤ 96
12w ≤ 96
w ≤ 96 : 12
w ≤ 8 cm
Zepler [3.9K]3 years ago
5 0
I hope this helps you

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