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2 years ago

HELP ASAP plz, 45 pts

Mathematics

1 answer:

torisob [31]2 years ago

8 0

Answer:

She didn't take the LCM, made an error while cross multiplying

x = -6

Step-by-step explanation:

a)she didn't take the LCM before cross multiplying.

Also, didn't cross multiply correctly

b) 1 -2/(x-2) = (x+1)/(x+2)

1 - 2/(x-2) = (x+2-1)/(x+2)

1 - 2/(x-2) = 1 - 1/(x+2)

-2(x+2) = -1(x-2)

-2x-4 = -x+2

x = -6

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I need help with coming up with equation

Natali5045456 [20]

Let's call a child's ticket $c$ and an adult's ticket $a$ . From this, we can say:

$c + a = 116$ ,

since 116 tickets are sold in total.

Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus

$\$17000 \cdot (1 - \dfrac{1}{4}) = \$12750$ .

Given these values, we can say:

$17000a + 12750c = 1653250$ ,

since each adult ticket $a$ costs 17,000 and each child's ticket $c$ costs 12,750, and these costs sum to 1,653,250.

Now, we have two equations:

$17000a + 12750c = 1653250$

$c + a = 116$

Let's solve:

$17000a + 12750c = 1653250$

$a = 116 - c$

Find $a$ on its own, which will allow us to substitute it into the first equation

$17000(116 - c) + 12750a = 1653250$

Substitute in $116 - c$ for $a$

$1972000 - 17000c + 12750c = 1653250$

Apply the Distributive Property

$1972000 - 4250c = 1653250$

Combine like terms

$4250c = 318750$

Subtract 1972000 from both sides of the equation and multiply both sides by -1

$c = 75$

We have now found that 75 child's tickets were sold. Thus,

$75 + a = 116 \Rightarrow a = 116 - 75 = 41$ ,

41 adult tickets were sold as well.

In sum, 41 adult tickets were sold along with 75 child tickets.

6 0

2 years ago

Exhibit 12-4 In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Li

Brums [2.3K]

Answer:d. uniformly distributed variable

Step-by-step explanation:Uniform Distribution Definition- in statistics , this mean an outcome is equally likely each variable has an equal or same probability to appear in an outcome.

For example in a deck of cards ,they are uniformly distributed which means the likelihood of drawing a club, a diamond , and a heart is the same.

When we see the percentage of how these students are distributed in art college and business college it is likely that one obtains a uniform distributed results.

8 0

2 years ago

Joanna plans on hanging 3 pictures of different sizes on the wall of her staircase. She thinks it will look best if all 3 rectan

Natasha2012 [34]

In similar figures, the ratio between corresponding sides are the same.

$\frac{25}{35}=\frac{35}{49}$

Simplify the two to see that they are equal.
The top and bottom of the left fraction are divisible by 5.
The top and bottom of the right fraction are divisible by 7.

$\frac{5}7=\frac{5}7$

Of course, the dimensions of that third picture would have to be this fraction.
Let's test these answers.

$\frac{5}6\neq\frac{5}7$ ⇒ A is not a solution

$\frac{30}{42}=\frac{5}7$ ⇒ B is the solution
(divide the top and bottom by 6)

5 0

3 years ago

What is 7999 +9100=?????????

Mama L [17]

the answer is 17099

6 0

3 years ago

Learning Task 3

ASHA 777 [7]

Answer:

1. The sides are: 38.5, 39.5, 40.5 and 41.5

2. Presently, Inzo is 15 years old and Miz is 10 years old

3. $Distance = 3682km$

4. Possible pairs are: (12, 14), (16, 18) and (20, 24)

5. $L < 38m$

Step-by-step explanation:

The question has lots of missing details. See the comment section for complete question

Solving (a):

Given

Shape: Quadrilateral

Sides: Consecutive

$Perimeter = 160$

Let one of the sides be x. The other sides will be x + 1, x + 2 and x + 3.

So, the perimeter is:

$Perimeter = x + x + 1 + x + 2 + x + 3$

This gives:

$160 = x + x + 1 + x + 2 + x + 3$

Collect Like Terms

$160 -1-2-3= x+x+x+x$

$154= 4x$

Divide both sides by 4

$38.5 = x$

$x =38.5$

So, the sides are: 38.5, 39.5, 40.5 and 41.5

Solving (b):

Given

Presently: $Inzo = 10 + Miz$

Five years ago: $Miz - 5= \frac{1}{3} * (Inzo-5)$ --- (Missing from the question)

Required: Determine their present ages

Substitute $10 + Miz$ for Inzo in the second equation

$Miz - 5 = \frac{1}{3} * (10 + Miz - 5)$

$Miz - 5 = \frac{1}{3} * (Miz + 5)$

Multiply both sides by 3

$3Miz - 15 = Miz + 5$

Collect Like Terms

$3Miz -Miz = 15 + 5$

$2Miz= 20$

Divide both sides by 2

$Miz = 10$

Substitute 10 for Miz in $Inzo = 10 + Miz$

$Inzo = 10 + 5$

$Inzo = 15$

So presently, Inzo is 15 years old and Miz is 10 years old

Solving (3):

Given

Express Train:

$Speed = 100kph$

$Time = t$

Local Train:

$Speed = 45kph$

$Time = t + 45$

Required: Determine the distance between A and B

Distance is calculated as:

$Distance = Speed * Time$

For the express train:

$Distance = 100 * t$

For the local train

$Distance = 45 * (45 + t)$

Distance between both stations are equal; So,

$100 * t = 45 * (45 + t)$

$100 t = 2025 + 45t$

Collect Like Terms

$100 t -45t= 2025$

$55t= 2025$

Divide by 55

$t = 36.82$

Substitute 36.82 for t in $Distance = 100 * t$

$Distance = 100 * 36.82$

$Distance = 3682km$

Solving (4):

Let the even numbers be: n and n + 2.

Sum greater than 24: $n + n + 2 > 24$

Sum less than 60: $n + n + 2 < 60$

So, we have:

$n + n + 2 > 24$

$2n + 2 > 24$

Collect Like Terms

$2n > 24-2$

$2n > 22$

$n > 11$

$n + n + 2 < 60$

$2n + 2< 60$

Collect Like Terms

$2n < 60-2$

$2n < 58$

Divide by 2

$n$

So, we have:

$n > 11$ and $n < 29$

So, possible pairs are: (12, 14), (16, 18) and (20, 24)

Solving (5):

Given

$Perimeter < 152m$

Required: Find the possible lengths

Let the length be L.

Perimeter is calculated as:

$Perimeter =4 * L$

$Perimeter =4 L$

So, we have:

$4L < 152m$

Divide through by 4

$L < 38m$

Hence, length is less than 38m (e.g. 37m)

5 0

2 years ago