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lubasha [3.4K]
3 years ago
8

True or False Plane KLM and Plane NQR are parallel planes

Mathematics
1 answer:
Nana76 [90]3 years ago
3 0

Answer:

i saed to answer it and it didnt show me the image so im conf

Step-by-step explanation:

so probably they are, unlees one is acxute and the other is obtuse then.... ur on ur own buddy,

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koban [17]

Answer:

2x + 3(8 - 3x) = 3

x = 3

y = -1

Step-by-step explanation:

2x + 3y = 3

y = 8 – 3x

2x + 3(8 - 3x) = 3

2x + 24 - 9x = 3

7x = 21

x = 3

y = 8 - 3(3)

y = -1

5 0
3 years ago
What is ( √2 - √3 )² =
allochka39001 [22]

just use FOIL (First, Outer, Inner, Last).

( √2 - √3 ) X ( √2 - √3 )

First: √2 X √2 = 2
Outer: √2 X -√3 = -√6
Inner: -√3 X √2 = -√6
Last: -√3 X -√3 = 3

and then add them together.

2 - √6 - √6 + 3
5 - 2(√6)

The answer is 5 - 2(√6) . 

4 0
3 years ago
Read 2 more answers
What makes a quadratic equation make sense?
siniylev [52]
When solving equilibrium problems a quadratic results it has the general form 0 equals x ^ 2 + BX + C a b and c may be positive or negative numbers usually when the wrong answer is plugged in it will lead to a negative concentration or amount. good luck
7 0
3 years ago
I WILL MARK U BRAINLYNEST
stiv31 [10]

Answer:

<h3>Step-by-step explanation:</h3>

A)answer: A cross section is the two-dimensional shape that results from cutting a three-dimensional with a plane.

B)answer: A cross section is the face you obtain by making a "slice" through a solid object. A cross section is two-dimensional. ... When a plane intersects a solid figure, the cross sectional face may be a point, a line segment, or a two-dimensional shape such as, but not limited to, a circle, rectangle, oval, or hexagon.

5 0
3 years ago
A square is formed by joining the midpoints of alternate sides of a regular octagon with side length 14 in. Find the shaded area
Darya [45]

Answer:

98(1 + 2√2) in² ≈ 375 in²

Step-by-step explanation:

Assuming the shaded region is outside of the square and inside of the octagon, we can find the area by subtracting the area of the square from the area of the octagon.

The area of a regular octagon is 2 (1 + √2) s².  We can show this by finding the area of the square outside of the octagon, and subtracting the triangles in the corners:

(s + √2 s)² − 4 (½ (½√2 s)²)

(1 + √2)² s² − 4 (½ (s²/2))

(1 + 2√2 + 2) s² − s²

2 (1 +√2) s²

The diagonal of the inner square is equal to the width of the octagon, (1+√2) s.  So the side length of the square is:

½√2 (1+√2) s

½(2+√2) s

The area of the square is therefore:

(½(2+√2) s)²

¼(2+√2)² s²

¼(4+4√2+2) s²

¼(6+4√2) s²

½(3+2√2) s²

The area of the shaded region is therefore:

2 (1 +√2) s² − ½(3+2√2) s²

½ s² (4 (1 +√2) − (3+2√2))

½ s² (4 + 4√2 − 3 − 2√2)

½ s² (1 + 2√2)

The side length of the octagon is s = 14 in, so the area is:

½ (14 in)² (1 + 2√2)

= 98(1 + 2√2) in²

≈ 375 in²

3 0
4 years ago
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