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vlada-n [284]
3 years ago
15

What are the key aspects of Daredevil Danny's practice jump shown in the graph provided?

Mathematics
1 answer:
motikmotik3 years ago
8 0

Answer:

the roots and vertex

Step-by-step explanation:

you can find the vertex by using vertex form y=a(x-h)^2+k you find the roots by solving the quadratic equation

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BO is included between
Otrada [13]

Answer:

Answer is given below with explanations.

Step-by-step explanation:

The correct answer is option d

BC is included between the angle B and C

Hence the answer is option d

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

7 0
3 years ago
Find the equation of the line The line has a slope of 1.3 and passes through the point (-2.3, -3.2)
irga5000 [103]

Answer:

y=1.3 x - 0.21

Step-by-step explanation:

y = (slope) \times x + (constant)

set (-2.3,-3.2) in above

- 3.2 = 1.3 \times ( - 2.3) + c

then c=-0.21

3 0
2 years ago
Find the general solution of (x+3)y’=2y
gregori [183]

Answer:

y=C(x+3)^2

Step-by-step explanation:

We are given:

\displaystyle (x+3)y^\prime=2y

Separation of Variables:

\displaystyle \frac{1}{y}\frac{dy}{dx}=\frac{2}{x+3}

So:

\displaystyle \frac{dy}{y}=\frac{2}{x+3} \, dx

Integrate:

\displaystyle \int\frac{dy}{y}=\int\frac{2}{x+3}\, dx

Integrate:

\displaystyle \ln|y|=2\ln|x+3|+C

Raise both sides to e:

|y|=e^{2\ln|x+3|+C}

Simplify:

|y|=(e^{\ln|x+3|})^2\cdot e^C

So:

|y|=C|x+3|^2

Simplify:

y=\pm C(x+3)^2=C(x+3)^2

5 0
3 years ago
Make it simple thanks
andriy [413]

Answer:

You can look for these:

Step-by-step explanation:

The factors of the equation:

For example, if multiplication, the factors 2x2=4

if addition, the addends 2 + 2= 4

So just look for the numbers before the equal sign and any key words in the problem.

Hope this helps!

5 0
2 years ago
Read 2 more answers
What's the answer to this problem
andrey2020 [161]
A, C, and D are true
4 0
3 years ago
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