Answer: AB = 8.4 BC = 12.4
Explanation:
Start of by solving AB using SOH CAH TOA and primary trig ratios;
AB is the opposite side and AC is the hypotenuse, so we use sin.
sin34 = AB/15
15 • sin34 = AB
8.4 ≈ AB
then, solve for BC
cos34 = BC/15
15 • cos34 = BC
12.4 = BC
Answer:
2 pounds
Step-by-step explanation:
Because 8 ounces = 0.5 pounds
1.5+0.5=2
So, since both equate to y, we can solve for x by equating the equations to each other.
4x - 5 = -3
So: 4x = 2
So: x = 1/2, or 0.5
Now, y = -3, so the solution is (0.5, -3)
You can graph the two equations, and the point where they meet will be (0.5, -3).
What is the outlier in the following data set:<br>
15,11,10,8,9,1,8,7,5,4,2,3, and 37?
NeTakaya
Step-by-step explanation:
The steps to find an outlier:
1. Put the data in numerical order.
2. Find the median.
3. Find the medians for the top and bottom parts of the data. This divides the data into 4 equal parts.
The median with the smallest value is called Q1. The median for all the values - usually just called the median is also called Q2. The median with the largest value is Q3.
4. Subtract...Q3 - Q1. This value is the InterQuartileRange or IQR. Remember that the range means taking the largest minus the smallest. This is a special range having to do with the quartiles.
5. Multiply...1.5 * IQR
6. Take your answer from #5 and do 2 things with it. A). Subtract it from Q1 and B) Additional to Q3.
7. Look at all your data points. If any are SMALLER than Q1 - 1.5 *IQR, they are outliers. If any are LARGER than Q3 + 1.5 *IQR, they are also outliers.
For your data....the median, Q2 is
(43+38)/2 = 40.5.
Q1 = (30+26)/2 = 28.
Q3 = (54+52)/2 = 53
The IQR is 53 - 28 = 25
1.5 * IQR = 37.5
Q1 - 37.5 = 28 - 37.5 = -9.5. There is no data value less than -9.5.
Q3 + 37.5 = 53 + 37.5 = 90.5. there is no data value greater than 90.5.
My conclusion is that there are no outliers in this data.
I hope this helps!
