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4 years ago

Whats the answer to this ?

Mathematics

2 answers:

tatyana61 [14]4 years ago

8 0

Answer:

C is the answer

Step-by-step explanation:

$149 is the cost of one soccer sets and s is the number of them

$127 is the cost of one volleyball set and v is the number of them

$275 is the cost of one football training set and the amount of them is f

mrs_skeptik [129]4 years ago

8 0

The answer to solve the problem is C

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Answer. it fast please

mojhsa [17]

Answer:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

Step-by-step explanation:

Given

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Required

Solve:

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Simplify 6/10

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2$

Express 9 as 3^2

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{3^2})^2$

Apply law of indices

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{3^4}$

Express as a sing;e fraction

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}$

Apply law of indices:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5*3}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

5 0

3 years ago

Help with 3 short questions

quester [9]

Sorry I have no idea

4 0

3 years ago

Read 2 more answers

1. Which of the following equations has a solution of x = -5? Equation A------> 16x-7=11x-32 Equation B------> -4x- 10=2x+

Nitella [24]

Answer:

Step-by-step explanation:

<u>Equation A</u>

16x - 7 = 11x - 32

(16x - 7) - 11x = (11x - 32) -11x

5x - 7 = -32

(5x - 7) + 7 = (-32) + 7

5x = -25

(5x)/5 = (-25)/5

x = -5

<u>Equation B</u>

-4x - 10 = 2x + 20

(-4x - 10) - 2x = (2x + 20) - 2x

-6x - 10 = 20

(-6x - 10) + 10 = (20) + 10

-6x = 30

(-6x)/-6 = (30)/-6

x = -5

Both Equation A and Equation B have a solution of -5.

4 0

3 years ago

A bicycle wheel with diameter 16 inches rides over a screw in the street. the screw is on level ground before it punctures the b

weqwewe [10]

The height of the screw = 16 inches.

<h3>How do you determine the number of revolutions in a circle?</h3>

The total distance covered in one revolution will be equal to the perimeter of the wheel. Finally, to find the total number of revolutions, divide the total distance by distance covered in one revolution.

Given that,

Diameter of a bicycle = 16 inches

The distance the bike moves (forward) after the screw punctures the tire = 56π inches

We note that the circumference of the bicycle = π·D = π × 16 = 16π inches

Therefore,

$\frac{56\pi }{16\pi }$ = 3.5

Showing that the bicycle moves three and half complete turns (revolution) where after each complete turn, the screw starts from the bottom of the tire.

The height, h of the screw in the final half turn is given by the relation;

h = A cos(Bx - C) + D

Where

A = Amplitude of the motion = Diameter/2 = 16/2 = 8

P = The period of the motion 2π/B

Bx = The angle described by the motion = Half of one revolution = π = 180°

C = Phase shift = π

D = The mid line = Diameter/2 = 8 inches

Therefore;

h = 8×cos(π - π) + 8 = 16 inches

Hence, After the bike moves forward another 56π inches the height of the screw = 16 inches.

To learn more about number of revolution from the given link:

brainly.com/question/17266654

#SPJ4

8 0

2 years ago

Example of A function whose domain is [2, infinity]

FrozenT [24]

$\\f(x)=\sqrt{x-2}
\\
\\g(x)=(x-1)^2+2$

6 0

3 years ago

Read 2 more answers