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trapecia [35]
3 years ago
14

The probability distribution for a game is shown in the table below.

Mathematics
1 answer:
nydimaria [60]3 years ago
4 0

Given:

It is given that

Probability of winning $ 0 = \frac{3}{10}

Probability of winning $ 100 = \frac{1}{5}

Probability of winning $ 200 = \frac{1}{10}

Probability of winning $ 500 = \frac{2}{5}

To find the probability of not winning a cash prize.

Explanation:

Not winning cash prize = winning $ 0

So,

Probability of not winning a cash prize

= Probability of winning $ 0

= \frac{3}{10}

Therefore,

The probability of not winning a cash prize is \frac{3}{10}. Option D.

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Given a sphere with radius r, the formula 4pi r^2 gives
Shkiper50 [21]

Answer:

Step-by-step explanation:

That's B:  the surface area.

The volume of the sphere is V = (4/3)πr³; A = 4πr² happens to be the derivative of V with respect to r.

8 0
3 years ago
The sum of four consecutive even integers is -28
mina [271]
I guess you want to find the 4 numbers

x + x + 2 + x + 4 + x + 6 = -28
4x + 12 = - 28
4x =  - 40
x = -10

so the numbers are -10, -8, -6 ,-4.

8 0
3 years ago
Factor 56-16 using the gcf
telo118 [61]

<h3>I hope it is helpful for you ...</h3>

3 0
3 years ago
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
3 years ago
How to solve (x-10)(x + 10)
tensa zangetsu [6.8K]

Answer:

Multiplying/simplifying, it is x^2-100(found by the FOIL method)

Step-by-step explanation:

multiply the commons factors x times x is x squared

-10 times 10 is -100. Negative times positive is negative.

6 0
3 years ago
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