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Soloha48 [4]
2 years ago
13

John ate 40% of the candies in a bag. If John ate 20 candies , how many candies were total in the bag ?

Mathematics
2 answers:
Zarrin [17]2 years ago
6 0

Answer:

50

Step-by-step explanation:

mina [271]2 years ago
3 0

Answer:50

Step-by-step explanation:

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What is the slope of a line that passes through (-4,-13) and (19,11)
inysia [295]
The slope of the line is the gradient, which you can find through rise over run

m (gradient) = (y1 - y2) / (x1 - x2)

where (x1, y1) is the coordinate of the first point, and (x2, x2) is the coordinate of the second point

in your question: 
x1 = -4
x2 = 19
y1 = -13
y2 = 11

m = (-13 -11) / (-4 -19) = -24 / -23 = 24/23 or 1.04 (2d.p.)

hope that helps :)
3 0
3 years ago
Read 2 more answers
Which statement is true ?
Jobisdone [24]

Answer:

b

Step-by-step explanation:

5 0
2 years ago
Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, \frac{1.2}{4}

= 0.3 collisions per  month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}


                                                           for x ∈ N ∪ {0}

                       =  0 otherwise --------------------------------------(1)

here, \lambda = 0.3 collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}


                      \simeq 0.7408182207 ------------------------------------(2)

Now, since we are calculating  this for 4 months,

so, P(No collision in 4 month period)

     =0.7408182207^{4}

     \simeq 0.3012  -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}


                      \simeq 0.2222454662 ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

                =0.2222454662^{2}

                \simeq 0.0494 -----------------------------------------(5)

1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

\simeq 0.6543894283-------------------------------------------(6)

So,

P(1  collision in 6 month period)

  =  0.6543894283^{6}

   \simeq 0.0785267444 ------------------------------------------------(7)

So,

P(No collision in 6 months period)

  = (P(X =0)^{6}

   \simeq 0.1652988882 ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

\simeq  0.2438 ---------------------------------------------(9)          

7 0
2 years ago
Please help! I really don't understand!
Varvara68 [4.7K]
A. yes this is a statistical question. it is a statistical question because you can answer the question by collecting data.


b. some clusters are.. 3,4,5, and 6 they are clusters because they are assembled around a particular value. the peak is 6 because it is the highest number it reaches. there are no gaps in this table.



c. to calculate the average with a graph you sum the numbers then divide by the total number of values in the set. for this table you add 1+2+3+3+4+4+4+5+5+5+5+5+5 then you divide by 15.

1+2+3+3+4+4+4+5+5+5+5+5+5=51

51 ÷ 15= 3.4



3 0
2 years ago
Allen bought a computer that was 25% off the regular price of $480.
Ilia_Sergeevich [38]

Answer:

144? or 126 sorry

Step-by-step explanation:

4 0
3 years ago
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