Question

A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test c e que tous
build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing in the


represents child bikes and a represents adult bikes, determine which system of inequality best explans whether the company and tes and 150


bikes in the week


No, because the bike order does not meet the restrictions of 40 + 6a s 120 and 4C + 4a s 100


No, because the bike order does not meet the restrictions of 40 + 4a s 120 and 6C + 4a 5 100


Yes, because the bike order meets the restrictions of 40 + 6a s 120 and 4C + 4a s 100


Yes, because the bike order meets the restrictions of 40 + 4a s 120 and 6c + 4a 5 100

Answer 1

As the question is unable to be understood/incomplete hence let's discuss the complete question (most probable question) and the answer for that.

Updated Question:

"A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test. Each adult bike requires 6 hours to build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. If c represents child bikes and a represents adult bikes, determine which system of inequality best explains whether the company can build 20 child bikes and 6 adult bikes in the week. No, because the bike order does not meet the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100 No, because the bike order does not meet the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100 Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100 Yes, because the bike order meets the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100"

Answer:

Correct answer for this question is first option because it satisfies the first inequality but not the second one.

Step by Step Explanation:

$NO,\\4c+6a\leq 120\\ and\\4c+4a\leq 100$

First Inequality:

4(20)+6(6)≤120

80+36≤120

116≤120 ⇒ TRUE

Second Inequality:

4(20)+4(6)≤100

80+24≤100

104≤100 ⇒ FALSE