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scoray [572]
3 years ago
9

D/12 = 0.25 bbhhgshdhrjrhfbbdb

Mathematics
1 answer:
marta [7]3 years ago
4 0
So solve for the placeholder D
D/12=0.25
multiply both sides by 12 to clear fraction
12D/12=0.25 times 12
D(12/12)=3
D(1)=3
D=3


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There are four more girls than boys in Ms. Raub's class of 28 students. What is the ratio of number of girls to the number of bo
Natasha_Volkova [10]
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Prove the polynomial identity.
aleksandr82 [10.1K]

Explanation:

Since we have given that

(2x+1)^2-2(2x+1)

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(2x+1)(2x-1)

Now, start the iterations:

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7 0
3 years ago
Write an equation of the line that passes through the given points (1 , 1.5) and (2, 3.5)
Nitella [24]

Answer:

y=2x-0.5

Step-by-step explanation:

typically, the equation of the line is written in slope intercept form, which is y=mx+b, where m is the slope and b is the y intercept

first, we need to find the slope (m) of the line

the formula for slope calculated from two points is given as (y2-y1)/(x2-x1)

we have two points: (1,1.5) and (2,3.5) and we can label them

x1=1

y1=1.5

x2=2

y2=3.5

now plug into the formula:

m=(3.5-1.5)/(2-1)

m=2/1

m=2

the slope of the line is 2

here's our equation so far:

y=2x+b

now we need to find b

since the line will pass through the points (1, 1.5) and (2, 3.5), we can plug either one of them into the equation to solve for

Let's use (1, 1.5)

substitute 1.5 as y and 1 as x

1.5=2(1)+b

1.5=2+b

subtract 2 from both sides

-0.5=b

therefore, our equation is:

y=2x-0.5

hope this helps!

5 0
3 years ago
What is the exact value of arccos(−2√2) ?
Strike441 [17]

Answer:

See explanation

Step-by-step explanation:

The range of the cosine function is -1\le \cos x\le 1

Therefore arc \cos (-2\sqrt{2}) is not defined.

Assuming your question is rather arc \cos (-\frac{\sqrt{2}}{2})

Then arc \cos (-\frac{\sqrt{2}}{2})=\pi-arc \cos (\frac{\sqrt{2}}{2})  in the second quadrant.

arc \cos (-\frac{\sqrt{2}}{2})=\pi-\frac{\pi}{4}

arc \cos (-\frac{\sqrt{2}}{2})=\frac{3\pi}{4}

4 0
3 years ago
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