Answer: 3 oxygen atoms!
Explanation: Let me know if I'm wrong, if not I'm happy to help!
Answer:
There are 0.0267 moles of oxygen in 0.658 grams of magnesium nitrate.
Explanation:
Mass of magnesium nitrate = m = 0.658 g
Molar mass of magnesium nitrate = M = 148 g/mol
Moles of magnesium nitrate = n
1 mole of magnesium nitrate has 6 moles of oxygen atoms. Then 0.004446 moles magnesium nitrate will have :
There are 0.0267 moles of oxygen in 0.658 grams of magnesium nitrate.
Answer : (C) 854.46 KPa.
Solution : Given,
Initial pressure = 400 KPa
Initial temperature = 110 K
Final temperature = 235 K
According to the Gay-Lussac's law, the absolute pressure is directly proportional to the absolute temperature at constant volume of an ideal gas.
P ∝ T
Formula used :
where,
= initial pressure
= final pressure
= initial temperature
= final temperature
Now put all the values in above formula, we get
By rearranging the terms, we get the value of new/final pressure.
= 854.5454 KPa 854.55 KPa
Answer:
6.98%
Explanation:
% error= |experimental value - actual value|/actual value × 100
Experimental value= 4.6 cm
Actual value= 4.3 cm
% error = |4.6-4.3|/4.3 × 100
% error = 6.98%
Loses one electron and becomes a positively <span>charged ion.
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