Question

A sample of carbon dioxide gas is reduced to 1/3 of its original volume while the pressure is observed to doubleplaced in a container the volume of the container is in the system did the temperature change?

Answer 1

Answer:

The temperature will change and become 2/3 of its original.

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,  

The volume of the sample gets reduced 1/3 of the original. So,

V₂ = 1/3V₁

The pressure of the sample is doubled of the original. So,

P₂ = 2P₁

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{2\times P_1}\times {\frac{1}{3}\times V_1}}{T_2}$

$T_2=\frac{2}{3}\times T_1$

The temperature will change and become 2/3 of its original.