Question

The length of a rectangular frame is 15 inches, and the width of the frame is 8 inches. what is the length of the diagonal of this frame in inches?​

Answer 1

Answer:

17 inches

Step-by-step explanation:

Length of the rectangular frame = 15 inches

Width of the rectangular frame = 8 inches

Let the length of the diagonal of the frame = l inches

Then, Square of the diagonal is the sum of the squares of length and width of the frame.

$\[l^{2}=8^{2}+15^{2}\]$

$\[=> l^{2}=64+225\]$

$\[=> l^{2}=289\]$

$\[=> l=17\]$

Hence the length of the diagonal of the frame is 17 inches.

Answer 2

Answer: the length of the diagonal of this frame is 17 inches.

Step-by-step explanation:

In the rectangular frame, the opposite sides are equal. The diagonal divides the rectangle into two equal right angle triangles. The diagonal represents the hypotenuse of both right angle triangles. The length and width represents the opposite and adjacent sides of the right angle triangles.

To determine the length, L of the diagonal of this frame, we would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

Therefore,

L² = 15² + 8²

L² = 225 + 64

L² = 289

L= √289

L = 17 inches