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Answer: Arun is now 20, Shree is 10 years old
Step-by-step explanation:
In the system of equations Arun's age is a. Shree is s
a = 2s .(current age equation) Subtract 5 from each for five years ago,
a-5 = 3(s-5) . Substitute 2s for a in the second equation
2s -5 = 3(s-5) distribute and reorganize
2s-5 = 3s -15 . 15 - 5 = 3s - 2s
10 = s . Substitute into the first equation to find a
a = 2(10)
a = 20
5 years ago Shree was 5 and Arun was 15
Answer:
Distance LM = 5.20 unit (Approx.)
Step-by-step explanation:
Given coordinates;
L(1, 4, 7) and M(2, 9, 8)
Find:
Distance LM
Computation:
Distance between three-dimensional plane = √(x2 - x1)² + (y2 - y1)² + (z2 - z1)²
Distance LM = √(2 - 1)² + (9 - 4)² + (8 - 7)²
Distance LM = √(1)² + (5)² + (1)²
Distance LM = √1 + 25 + 1
Distance LM = √27
Distance LM = 3√3 unit
Distance LM = 3(1.732)
Distance LM = 5.196
Distance LM = 5.20 unit (Approx.)
Answer:
(x - 6)(x - 11)
Step-by-step explanation:
x² - 17x + 66
-11 and -6
x² -11x - 6x + 66
x(x -11) - 6(x -11)
(x - 6) (x - 11)
(x = 6 or x = 11) These are the possibilities of x
Answer: y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2
Step-by-step explanation:
vertex form is y=a(x-h)^2 + k
here we can see the vertex is (3,0) which is (x,y). Or (h,k) in this case.
so to plug that into vertex form, we now have y=a(x-3)^2 + 0. or just y=a(x-3)^2.
now we need to find "a" which is the leading coefficient. to do that we can plug in the (6,-6) for the x and y parts of the above equation. so we'd have
-6=a(6-3)^2. which goes to -6=a(2)^2 which is -6=4a. divide each side by 4 to get a = -2/3. plug this in for a
the final equation would be y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2