(x+2)(4+y)(5+6)(2+x)(4+0.5x)
combine like terms
(x+2) (4+y) (11) (x+2) (4+.5x)
11(x+2)^2 (4+y)(4+.5x)
distribute
11(x^2 +4x+2) (16+4y+2x+.5xy)
(11x^2+44x+22)(16+4y+2x+.5xy)
5.5 x^3 y + 22 x^3 + 66 x^2 y + 264 x^2 + 198 x y + 792 x + 176 y + 704
Answer: hope it helps
Step-by-step explanation:
2x+11 absolute value equals 2x+11, then 2x+11=7, subtract 11 from itself, and 7 you get 2x=4 divide both sides by 2 an you get -2=x.
Answer:
i need help with something like that aswell
Step-by-step explanation:
Answer: B. Funds need to be easily accessible
This is so you can access it easily without paying a penalty
Answer:
-2, 8/3
Step-by-step explanation:
You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...
A = (1/2)(f(a) +f(4))(4 -a)
= (1/2)((3a -1) +(3·4 -1))(4 -a)
= (1/2)(3a +10)(4 -a)
We want this area to be 12, so we can substitute that value for A and solve for "a".
12 = (1/2)(3a +10)(4 -a)
24 = (3a +10)(4 -a) = -3a² +2a +40
3a² -2a -16 = 0 . . . . . . subtract the right side
(3a -8)(a +2) = 0 . . . . . factor
Values of "a" that make these factors zero are ...
a = 8/3, a = -2
The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.
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<em>Alternate solution</em>
The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.