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Oksana_A [137]
2 years ago
13

If f (x) = StartRoot x minus 3 EndRoot, which inequality can be used to find the domain of f(x)?

Mathematics
1 answer:
kap26 [50]2 years ago
4 0

Given:

The function is:

f(x)=\sqrt{x-3}

To find:

The inequality that is used to find the domain of the given function.

Solution:

We have,

f(x)=\sqrt{x-3}

We know that the radical functions are defined for only positive values of radicand.

It means the given function is defined if the value of (x-3) is greater than or equal to 0.

x-3\geq 0

Adding 3 on both sides, we get

x-3+3\geq 0+3

x\geq 3

The inequality x-3\geq 0 is used to find the domain of the given function and the domain of the given function is x\geq 3.

Therefore, the correct option is B.

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5 0
3 years ago
Arun is twice as old as Shreet 5 years ago his age was three times shree age find their present ages​
Mariulka [41]

Answer:  Arun is now 20, Shree is 10 years old

Step-by-step explanation:  

In the system of equations Arun's age is a. Shree is s

a = 2s .(current age equation)  Subtract 5 from each for five years ago,

a-5 = 3(s-5) . Substitute 2s for a in the second equation

2s -5 = 3(s-5)  distribute and reorganize

2s-5 = 3s -15 .   15 - 5 = 3s - 2s

10 = s .  Substitute into the first equation to find a

a = 2(10)

a = 20

5 years ago  Shree was 5 and Arun was 15

7 0
3 years ago
Read 2 more answers
14
Nuetrik [128]

Answer:

Distance LM = 5.20 unit (Approx.)

Step-by-step explanation:

Given coordinates;

L(1, 4, 7) and M(2, 9, 8)

Find:

Distance LM

Computation:

Distance between three-dimensional plane = √(x2 - x1)² + (y2 - y1)² + (z2 - z1)²

Distance LM = √(2 - 1)² + (9 - 4)² + (8 - 7)²

Distance LM = √(1)² + (5)² + (1)²

Distance LM = √1 + 25 + 1

Distance LM = √27

Distance LM = 3√3 unit

Distance LM = 3(1.732)

Distance LM = 5.196

Distance LM = 5.20 unit (Approx.)

5 0
3 years ago
PLEASE HELP! REWARDING A LOT :)
vaieri [72.5K]

Answer:

(x - 6)(x - 11)

Step-by-step explanation:

x² - 17x + 66

-11 and -6

x² -11x - 6x + 66

x(x -11) - 6(x -11)

(x - 6) (x - 11)

(x = 6 or x = 11) These are the possibilities of x

4 0
3 years ago
Read 2 more answers
I have to transfer this graph into a vertex form equation, but I'm not sure how to.​
tino4ka555 [31]

Answer: y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2

Step-by-step explanation:

vertex form is y=a(x-h)^2 + k

here we can see the vertex is (3,0) which is (x,y). Or (h,k) in this case.

so to plug that into vertex form, we now have y=a(x-3)^2 + 0. or just y=a(x-3)^2.

now we need to find "a" which is the leading coefficient. to do that we can plug in the (6,-6) for the x and y parts of the above equation. so we'd have

-6=a(6-3)^2. which goes to -6=a(2)^2 which is -6=4a. divide each side by 4 to get a = -2/3. plug this in for a

the final equation would be y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2

8 0
2 years ago
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