(1) Write the net ionic equation for the reaction that occurs when equal volumes of 0.233 M aqueous acetylsalicylic acid (aspiri
n) and aniline are mixed. It is not necessary to include states such as (aq) or (s).
2 answers:
Complete Question
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Answer:
1) The ionic equation is
2
At equilibrium The aniline will be favored
3
The pH of the solution is
Explanation:
From the question we are told that
The concentration of aspirin is
The acid dissociation constant for aspirin is
The base dissociation constant for aniline is
The molecular formula for aspirin is
The molecular formula for aniline is
So the net ionic reaction is
Generally pKa is mathematically evaluated as
Generally pKb is mathematically represented as
Generally
pKa + pKb = 14
So for the triethylammonium salt produced the pKa is
As a result of the pKa of aspirin being lower that that of triethylammonium salt at equilibrium it implies that aniline would be favored
The pH of the solution is mathematically represented as
Since they are of equal mole
Where pKw is the pKw of water which has a value of 14
Answer:
Check the explanation
Explanation:
Ka for aspirin =
Therefore,
pKa = - log() = 3.52
Kb for Triethylamine = 5.2 x 10-4
Therefore,
pKb = -log() = 3.28
We have,
pKa + pKb = 14
pKa = 14 – pKb = 10.71
pKa for the triethylammonium salt = 10.71
The net ionic reaction can be written as,
⇒
Since pKa of Aspirin is lower (3.52) than that of triethylammonium salt (10.71), at equilibrium triethyl amine will be favored.
pH of equimolar solution can be calculated as,
pH = ½ (pKw + pKa –pKb) = ½ (14 + 3.52 – 3.28) = 7.12
pH of resulting solution = 7.12
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