Question

calculate the amount of energy (in kJ) to convert 337 grams of liquid water from 0 degrees celsius to water vapor at 177 degrees celsius.

Answer 1

Answer:

The mount of heat required is 249.690 kJ.

Explanation:

Mass of the water,m =337 g

Specific heat capacity of the water,c = 4.186 J/g °C

Change in temperature =$\Delta T=177^oC-0^oC=177^oC$

Q = Heat required

$Q=mc\Delta T=337 g\times 4.186 J/g ^oC\times 177^oC=249,690.7 J=249.690 kJ$

1 kilo Joule = 1000 joules

The mount of heat required is 249.690 kJ.

Answer 2

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