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Elis [28]
3 years ago
13

calculate the amount of energy (in kJ) to convert 337 grams of liquid water from 0 degrees celsius to water vapor at 177 degrees

celsius.
Chemistry
2 answers:
Ganezh [65]3 years ago
6 0

Answer:

The mount of heat required is 249.690 kJ.

Explanation:

Mass of the water,m =337 g

Specific heat capacity of the water,c = 4.186 J/g °C

Change in temperature =\Delta T=177^oC-0^oC=177^oC

Q = Heat required

Q=mc\Delta T=337 g\times 4.186 J/g ^oC\times 177^oC=249,690.7 J=249.690 kJ

1 kilo Joule = 1000 joules

The mount of heat required is 249.690 kJ.

Ghella [55]3 years ago
3 0
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