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mylen [45]
3 years ago
7

When performing a flame test using the method described in the manual, you complete the flame test of KNO3 and find a yellow col

or instead of the expected purple color. Select the potential sources of error. Group of answer choices The nichrome wire is not hot enough. The solution is not concentrated enough. The flame is not optimized. The nichrome wire is dirty. The solution is contaminated. The watch glass is dirty.
Chemistry
1 answer:
jolli1 [7]3 years ago
7 0

Answer:

The nichrome wire is dirty.

The solution is contaminated.

Explanation:

If the nichrome wire is dirty, it may contain sodium contaminants which may be responsible for the yellow flame. The nichrome wire is first inserted into the flame without the sample to check for impurities.

The test solution may also have been contaminated. This leads to the appearance of a colour different from the expected colour of the test cation in the solution.

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Fatty acids are ________ Group of answer choices composed of carbon, hydrogen, and oxygen in a 1:2:1 ratio. composed of carbon,
VLD [36.1K]

Fatty acids are composed of hydrocarbon chains and a carboxyl group.

<h3>What are Fatty acids ?</h3>

Fatty acids are the building blocks of the fat in our bodies and in the food we eat.

During digestion, the body breaks down fats into fatty acids, which can then be absorbed into the blood.

Fatty acid molecules are usually joined together in groups of three, forming a molecule called a triglyceride.

Generally, a fatty acid consists of a straight chain of an even number of carbon atoms, with hydrogen atoms along the length of the chain and at one end of the chain and a carboxyl group (―COOH) at the other end.

It is that carboxyl group that makes it an acid (carboxylic acid).

Learn more about Fatty Acids here ;

brainly.com/question/13528495

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7 0
2 years ago
. A bright violet line occurs at 435.8 nm in the emission spectrum of mercury vapor. What amount of energy, in joules, must be r
Tom [10]

Answer :  The energy released by an electron in a mercury atom to produce a photon of this light must be, 4.56\times 10^{-19}J

Explanation : Given,

Wavelength = 435.8nm=435.8\times 10^{-9}m

conversion used : 1nm=10^{-9}m

Formula used :

E=h\times \nu

As, \nu=\frac{c}{\lambda}

So, E=h\times \frac{c}{\lambda}

where,

\nu = frequency

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength = 435.8\times 10^{-9}m

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{(435.8\times 10^{-9}m)}

E=4.56\times 10^{-19}J

Therefore, the energy released by an electron in a mercury atom to produce a photon of this light must be, 4.56\times 10^{-19}J

3 0
3 years ago
A sample of pure lithium chloride contains 16% lithium by mass. What is the % lithium by mass in a sample of pure lithium carbon
Anna35 [415]

Answer:

Percentage lithium by mass in Lithium carbonate sample = 19.0%

Explanation:

Atomic mass of lithium = 7.0 g; atomic mass of Chlorine = 35.5 g; atomic mass of carbon = 12.0 g; atomic mass of oxygen = 16.0 g

Molar mass of lithium chloride, LiCl = 7 + 35.5 = 42.5 g

Percentage by mass of lithium in LiCl = (7/42.5) * 100% = 16.4 % aproximately 16%

Molar mass of lithium carbonate, Li₂CO₃ = 7 * 2 + 12 + 16 * 3 =74.0 g

Percentage by mass of lithium in Li₂CO₃ = (14/74) * 100% = 18.9 % approximately 19%

Mass of Lithium carbonate sample = 2 * 42.5 = 85.0 g

mass of lithium in 85.0 g Li₂CO₃ = 19% * 85.0 g = 16.15 g

Percentage by mass of lithium in 85.0 g Li₂CO₃ = (16.15/85.0) * 100 % = 19.0%

Percentage lithium by mass in Lithium carbonate sample = 19.0%

3 0
3 years ago
How many moles of water produced from 13.5 mol of oxygen
skad [1K]

Answer:

diffrent types of maks and modles

Explanation:

3 0
3 years ago
Hook GC lsshvrrjvdjscavsbsgd​
Tema [17]

Answer:

I have no idea what that issss

Explanation:

6 0
3 years ago
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