Answer:
f(1) = 16
Domain: 0 ≤ t ≤ 2
Step-by-step explanation:
Given
f(t) = -16t²+ 32t
Solving (a): f(1)
Substitute 1 for t in f(t)
f(t) =− 16t²+ 32t .
f(1) =− 16 * (1)²+ 32 * 1
f(1) = -16 * 1 + 32
f(1) = -16 + 32
f(1) = 16
Solving (b): The domain
The implication of the given parameter in (b) is that t ≤ 2.
Since t represents time, t can't be negative.
Hence, a reasonable domain is
0 ≤ t ≤ 2
Answer:
Step-by-step explanation:
I answered another one of your questions so I will not explain as much. ther are 12 inches in a foot and then 5280 feet in a mile so that's 1 ft/ 12 in and 1 mi/ 5280 ft. So the math is 20 in * 1 ft/ 12 in * 1 mi/ 5280 ft = .000315 mi.
In reference to the last one, do keep in mind "square" inches and whatnot mean you square things. so 1 ft/ 12 in becomes 1 ft^2/ 144 in^2. Just as a small heads up to what could be tricky.
-10 = -10 + 7m
Add 10 to each side: 0 = 7m
Divide each side by 7 : 0 = m
Please take a second and just LOOK at the equation you started with.
It says:
-- You have this number '-10' .
-- Your number -10 is going to be exactly the same size
after you add 7 of something to it.
The ONLY way that could happen is if the 'something' is 'nothing' .
' m ' must be nothing.
