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3 years ago

7

I need to find Y=Mx+b. I found M but i forgot how to find B. Help

1 answer:

enot [183]3 years ago

3 0

Y = mx + b. This linear graph passes through A(0,50) and B(10,51)

m = (y₂-y₁)/(x₂-x₁)
m= (51-50)/10-0)
m=(1)(10)

y = (1/x) + b. To find b, you plugin the coordinates of either A or B,
say A(0,50):

50 = (1/10).(0) + b
50 = 0+b and b= 51

Hence the equation is y =0.1x + 50

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a system of equations is graphed here. which system of equations does the graph represent? A) y = 3x + 2y = -2x + 5 B) y = 3x -

n200080 [17]

Notice that the line with negative slope has a y-intercept of 5 and the line with positive slope has a y-intercept of 2.

On the other hand, the slope of the line with negative slope is -2, while the slope of the line with positive slope is 3 (This can be identified since in one case, the value of y decreases by 2 for each increase of 1 unit in x, and in the other, the value of y increases by 3 for each increase of 1 unit in x).

Using the y-intercept form to represent each line, the system of equations represented by the graph must be equivalent to:

$\begin{gathered} y=-2x+5 \\ y=3x+2 \end{gathered}$

From the given options, the one that displays the correct system of equations is option A.

Therefore, the answer is:

$\begin{gathered} A) \\ y=3x+2 \\ y=-2x+5 \end{gathered}$

6 0

1 year ago

Please solve for x z=m+x

SIZIF [17.4K]

Answer:

x = z - m

Step-by-step explanation:

<u>Solving for x with steps:</u>

z=m+x
x + m = z
x + m - m = z - m
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3 0

3 years ago

Select all the fractions that are equivalent to each other.

pogonyaev

1/4
2/8
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4 0

3 years ago

Read 2 more answers

Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3

Nikitich [7]

Answer:

option D

Step-by-step explanation:

$f(x) = x^2 + 5x + 6$

$g(x)= \frac{1}{x+3}$

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x in f(x)

$f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6$

To simplify it we take LCD

LCD is (x+3)(x+3)

$\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}$

$\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}$

All the denominators are same so we combine the numerators

$\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}$

$\frac{6x^2+41x+70}{x^2+6x+9}$

Option D is correct

8 0

2 years ago

Read 2 more answers

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Ulleksa [173]

40.604 is your answer

4 0

3 years ago