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puteri [66]
3 years ago
6

Suppose that two cards are randomly selected from a standard​ 52-card deck. ​(a) what is the probability that the first card is

a spadespade and the second card is a spadespade if the sampling is done without​ replacement? ​(b) what is the probability that the first card is a spadespade and the second card is a spadespade if the sampling is done with​ replacement?
Mathematics
1 answer:
Savatey [412]3 years ago
8 0
(a) without replacement:
P(S)=13/52=1/4
P(SS)=(1/4)*(12/51)=1/17
Probability of selecting two spades without replacement is 1/17.

(b) with replacement
P(S)=13/52=1/4
P(SS)=(1/4)(13/52)=1/16
Probability of selecting two spades with replacement is 1/16.
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PC-CSIL
pav-90 [236]

The equality used is Subtraction property of equality

Option A is correct

Step-by-step explanation:

We need to identify which option best explains or justifies Step 1.

Step 1 is: -c = ax^2 + bx

The given equation is: 0 = ax^2 + bx + c

To get the equation for step 1 we need to subtract c on both sides of equation i.e using subtraction property of equality

0-c = ax^2 + bx + c-c

-c = ax^2 + bx

So, The equality used is Subtraction property of equality

Option A is correct.

Keywords: Solving Quadratic Equations

Learn more about Solving Quadratic Equations at:

  • brainly.com/question/4460262
  • brainly.com/question/7361044
  • brainly.com/question/1414350

#learnwithBrainly

5 0
3 years ago
On Thursday, a company received 10 boxes with 16 desk calendars
Jet001 [13]

Answer:

340

Step-by-step explanation:

10 ×16=160

12×15=180

160+180=340 so a total of 340 calendars

3 0
2 years ago
I give 20! Help pleasee
Alexeev081 [22]

Answer:

29cm

Step-by-step explanation:

just add them all up

3 0
2 years ago
Ok so umm last question for tonight i hope but um please help
amid [387]

Answer:

fish=3,5,15

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Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Which piece of additional information can be used to prove △CEA ~ △CDB?
Slav-nsk [51]

<u>Answer-</u>

<em>The correct answer is</em>

<em>∠BDC and ∠AED are right angles</em>

<u>Solution-</u>

In the ΔCEA and ΔCDB,

m\angle BCD=m\angle ACE

As this common to both of the triangle.

If ∠BDC and ∠AED are right angles, then m\angle E=90=m\angle D

Now as

∠BCD = ∠ACE and ∠BDC = ∠AED,

∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)

Then, ΔCEA ≈ ΔCDB

Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.


5 0
3 years ago
Read 2 more answers
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