Answer:
1496.52 Pa, 14.76 atm
Step-by-step explanation:
This question can be solved using ideal gas law
according to which
pv = nrt
where p is the pressure of gas
v is volume of gas
n is amount gas in moles
R is ideal gas constant whose value is 8.314 J/mol
T is absolute temperature of gas on Kelvin scale
______________________________
given
v = 5 liter
n = 3
T = 300 kelvin
R = 8.314 J/mol
Let the pressure be p
Substituting the above value in ideal gas law equation we have
p*5 = 3*8.314*300
p = 7482.6/5 = 1496.52 Pa
This pressure is in pascal while option is in atm
we know 1 Pascal is equal to 0.0000098692 atm
we know that 1 Atm = 101325 Pa
thus, 1496.52 is equal to 0.0000098692*1496.52 atm
1496.52 is equal to 14.76 atm
Answer:
13 cents
Step-by-step explanation:
2.36/18= 0.13
<span>0.9% glucose solution means there are 0.9 g of glucose per 100 mL water.
</span><span> The concentration is required per litre for molar concentration:
0.9% glucose solution contains 9 g of glucose per 1000 mL or 1 L of water.
Molar mass of glucose is 180.16 g mol^-1 so 9 g = 9g/180.16 g mol^-1 = 0.05 moles
</span><span> 1 L of water contains 0.05 moles of glucose so molar concentration is 0.05 M or 0.05 mol/L </span>
Answer:
n=36
Step-by-step explanation:
36 divided by 2 is 16 then subtract 10 and you will get 6 hope this helps
