Given:
The graph of a line.
To find:
The point-slope form of the given line.
Solution:
From the given graph it is clear that the line passes through the point (1,5) and (0,-1). So, the slope of the line is:
The slope of the line is 6 and it passes through the point (1,5). So, the point slope form of the line is:
Therefore, the point-slope form is , slope is 6 and the point is (1,5).
Answer:
<76
Step-by-step explanation:
Remark
You can't do this problem unless CD and E are all on the same line. If they are, then you can use || line properties.
Properties
<ABG = x Given
<ABG = <BGF Alternate interior angles are equal.
<BGF = x Substitute
x + 2x - 9 = 180 Consecutive angles in a ||gram equal 180 degrees.
3x - 9 = 180 Add 9 to both sides
3x - 9 +9 = 180 +9
3x = 189 Divide by 3
x = 63
<DHG = 2x - 50 Given
<DHG = 2*63 - 50 Substitute for x
<DHG = 76
<IDC = 76
<DHG and <IDC are corresponding angles and are equal; it is a property of parallel lines.
4.555
4.556
4.557
4.558
4.559
4.561
4.562
4.563
4.564
The measure of ∠BEC would be 80 degrees
