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3 years ago

Solve the quadratic equation -x^2=4

Mathematics

2 answers:

tester [92]3 years ago

8 0

$-x^2 = 4$
$(-x)(-x) = 4$
$x^2 = 4$
$x = 2$

So, 2 is the answer.

Alex_Xolod [135]3 years ago

7 0

-x^2=4
x = -2i and x = 2i
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wariber [46]

Answer:

Step-by-step explanation:

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$Slope =\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$= \frac{10-[-2]}{3-[-1]}\\\\=\frac{10+2}{3+1}\\\\=\frac{12}{4}\\\\=4$

m = 4

y - y₁ = m (x - x₁)

y - [-2] = 4(x - [-1])

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y + 2 = 4x + 4

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If Levi purchased a total of 50 ride tickets and game tickets at the amusement park and spent $29. If right tickets cost $.75 ea

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Answer: he purchased 16 ride tickets.

Step-by-step explanation:

Let x represent the number of ride tickets that he purchased.

Let y represent the number of game tickets that he purchased.

Levi purchased a total of 50 ride tickets and game tickets at the amusement park. It means that

x + y = 50

If ride tickets cost $.75 each and game tickets cost $.50 each and the total amount spent on the tickets is $29, it means that

0.75x + 0.5y = 29- - - - - - - - - - - -1

Substituting x = 50 - y into equation 1, it becomes

0.75(50 - y) + 0.5y = 29

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Solve using the elimination method: X-3y=7 3x + 3y=9

sergij07 [2.7K]

Answer:

$x=4\\\\y=-1$

Step-by-step explanation:

Given Equation:

$x-3y=7$ Equation:1

$3x + 3y=9$ Equation:2

Dividing Equation:2 by '3' both the sides:

$x+y=3$

or $x=3-y$ Equation:3

Putting the vale of 'x' in Equation:1

$x-3y=7$

$(3-y)-3y=7\\\\3-y-3y=7\\\\3-4y=7\\\\$

Subtracting '3' both sides

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$y=-1$

Putting value of 'y' in Equation:3

$x=3-y$

$x=3-(-1)\\\\x=3+1\\\\x=4$

The solution of the equations is :

$x=4\\\\y=-1$

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