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Aleksandr-060686 [28]
3 years ago
9

Error Analysis

Mathematics
1 answer:
aleksklad [387]3 years ago
6 0

The coefficient(s) of the expression is/are 7, 1

Use a comma to separate answers as needed.)

The constant(s) of the expression is/are 8

(Use a comma to separate answers as needed.)

What error might Jake have made?

OD. Jake did not include the coefficient 1.

Click to select your answer's

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Does anyone know how to solve (2 Times x) + 5 =31
Anika [276]
X = 13 hope it helped
8 0
4 years ago
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Which statement could be used to explain why f(x)=2x-3 has an inverse relation that is a function
Gwar [14]
The <u>correct answer</u> is:

The function is a one-to-one function.

Explanation:

When an equation is graphed, we use the Vertical Line Test to determine if that equation is a function; if a vertical line hits more than one point anywhere on the graph, the graph is not a function.

This corresponds with the definition of a function:  A function is a set of ordered pairs in which each element of the domain (x) is mapped to no more than one element of the range (y).  Since every x has no more than one y, there will be no two points hit by the same vertical line.

When we have the graph of a function, to determine if it has an inverse, we use the Horizontal Line Test: if a horizontal line hits more than one point anywhere on the graph, the function does not have an inverse.

This corresponds with the definition of a one-to-one function:  A function in which every element of the range (y) is mapped to exactly one element of the domain (x). Since every y has one x, there will be no horizontal line that hits more than one point anywhere on the graph.
7 0
3 years ago
Read 2 more answers
Lynn Jude and Anne were given the function f(x)=2x^2+6, and they were asked to find f(-4). Lynns answer was 38, Judes answer was
Cerrena [4.2K]

Answer:

Lynn's answer 38 is correct

2(-4)^2+6

2(16)+6

32+6=38

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If vector v has an initial point at P1 and a terminal point at P2, write v as multiples of the basis vectors That is, write v in
pantera1 [17]

Answer:

v=9i+3j

Step-by-step explanation:

The given vector, v has initial point at P1 = (−5, −2) and terminal point at P2 = (4, 1).

The vector v is found by subtraction the initial point from the terminal point.

v=<4,1>-<-5,-2>

v=<4--5,1--2>

v=<9,3>

We write v as multiples of the basis vectors to obtain:

v=9i+3j

8 0
3 years ago
Solve each equation and leave the answer in terms of “i”
almond37 [142]
17)
x² + 8 = -8
x² = -8 - 8
x² = 16
x = ±√-16
x = ±√16i
x = <span>±4i
</span>
18)
x² + 5 = -3
x² = -3 - 5
x² = -8
x = ±√-8
x = ±√8i
x = ±2√2i

19)
x² + 3 = 0
x² = -3
x = ±√-3
x = <span>±</span>√3i

hope this helps, God bless!
3 0
3 years ago
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