Step-by-step explanation:
it it can be calculated by using the quadratic formula.
X=-b+_(√b^2-4ac)/2a
A metal ball of mass 100 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 2.5 kJ. Another metal ball
2 answers:
<span>specific heat (
) - the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree)
the equation related to this theory is
</span><span>
Where Q is the energy gained or lost from the system
m is the mass of the object
</span><span>
is the specific heat of the material
is the change in temperature
</span>
the equation related to this theory is
</span><span>
Where Q is the energy gained or lost from the system
m is the mass of the object
</span><span>
</span>
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Answer:
Step-by-step explanation:
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∴
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∴
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Answer:
The original duration of the tour is 18 days.
Step-by-step explanation:
Let
the number of days spent be T
Daily expenses be D
Initially ,
total tour expenses was 360
-------------(1)
If he extends his tour for 4 days, he has to cut down his daily expenses by dollar 3
---------------(2)
Expanding the eqaution(2)
DT-3D + 4T -12 = 360
Substituting the value of D
Solving the quadratic equation we get
T = 18 and T = -15
T is the number of gays and it cannot be negative , hence T is 18
Substituting in equation (1) we get
D = 20