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vovikov84 [41]
4 years ago
7

A metal ball of mass 100 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 2.5 kJ. Another metal ball

of mass 200 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 5.0 kJ. What can be concluded from the data?
Mathematics
2 answers:
WINSTONCH [101]4 years ago
8 0

Answer:

The balls are made of the same material.

Step-by-step explanation:

got it right :)

frosja888 [35]4 years ago
5 0
<span>specific heat (C_p &#10;) - the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree)

the equation related to this theory is
</span><span>Q=mC_p \Delta T

Where Q is the energy gained or lost from the system
m is the mass of the object
</span><span>C_p is the specific heat of the material
\Delta T is the change in temperature

</span>
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Step-by-step explanation:

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The quadrilateral is a rhombus.<br> If EF = 13 and DF = 18, find EH to the nearest tenth.
-Dominant- [34]

Answer:

EH = 9.4

Step-by-step explanation:

A rhombus is a quadrilateral with equal length of sides.

Given that,  EF = 13 and DF = 18

⇒ DH = HF = \frac{18}{2}

             = 9

The property that the diagonals of a rhombus are at right angle to each other.

Thus, applying the Pythagoras theorem, we have;

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169 =  (EH)^{2} + 81

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3 years ago
W (n) = n^2-n find w (-3)
Papessa [141]

Answer:

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Step-by-step explanation:

Plug in -3 for n in the equation:

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Next, combine like terms. Note that if there are two negative signs directly next to each other, it becomes a positive sign. Add:

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