Question

A metal ball of mass 100 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 2.5 kJ. Another metal ball of mass 200 g is heated to 90°C and then cooled to 25°C. The heat lost in the process is 5.0 kJ. What can be concluded from the data?

Answer 1

Answer:

The balls are made of the same material.

Step-by-step explanation:

got it right :)

Answer 2

specific heat ($C_p$) - the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree)

the equation related to this theory is
$Q=mC_p \Delta T$

Where Q is the energy gained or lost from the system
m is the mass of the object
$C_p$ is the specific heat of the material
$\Delta T$ is the change in temperature