Because the distance a car travels is directly related to the time it travels, the distance varies directly with the time: d=a*t. "a" would be the constant of variation. Just substituted the given values(300 and 5) into the equation, and you would get 300=5a. Divide both sides by 5 and you get a=60. So, the constant of variation is 60

3 0

4 years ago

Solve the equation. Type your answer in the box as positive or negative whole number (Examples: 2 -4 6 -8)

xxTIMURxx [149]

Answer:

-6n-5=31

Step-by-step explanation:

-6n=36

n=36/-6

n=(-6)

6 0

3 years ago

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Find the curl and the divergence of the vector field f(x, y, z) = x2yz i + xy2z j + xyz2 k

xxTIMURxx [149]

$\mathbf f(x,y,z)=x^2yz\,\mathbf i+xy^2z\,\mathbf j+xyz^2\,\mathbf k$

$\mathrm{div}\mathbf f(x,y,z)=\dfrac{\partial(x^2yz)}{\partial x}+\dfrac{\partial(xy^2z)}{\partial y}+\dfrac{\partial(xyz^2)}{\partial z}$
$=2xyz+2xyz+2xyz$
$=6xyz$

$\mathrm{curl}\mathbf f(x,y,z)=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\\\\frac\partial{\partial x}&\frac\partial{\partial y}&\frac\partial{\partial z}\\\\x^2yz&xy^2z&xyz^2\end{vmatrix}$
$=\left(\dfrac{\partial(xyz^2)}{\partial y}-\dfrac{\partial(xy^2z)}{\partial z}\right)\,\mathbf i-\left(\dfrac{\partial(xyz^2)}{\partial x}-\dfrac{\partial(x^2yz)}{\partial z}\right)\,\mathbf j+\left(\dfrac{\partial(xy^2z)}{\partial x}-\dfrac{\partial(x^2yz)}{\partial y}\right)\,\mathbf k$
$=\left(xz^2-xy^2\right)\,\mathbf i-\left(yz^2-x^2y\right)\,\mathbf j+\left(y^2z-x^2z\right)\,\mathbf k$

6 0

4 years ago

Riley bought 3.5 pounds of dried apples. They cost $2.56 per pound. How much did Riley pay for the dried apples? QUICK PLEASE !!

postnew [5]

Answer:

$8.96

Step-by-step explanation:

3.5 x 2.56 = 8.96

8 0

3 years ago

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