Let Cynthia's age be C, then Abigail's age A
since Abigail is 8 years older, her age A = C+8.
20 years ago Cynthia's she was C-20 and Abigail was A-20=3(C-20)
A-20=3C-60
A=3C-40
but we just said A=C+8
so 3C-40=C+8
2C=48
C=24
A=24+8=32
Cynthia's age is 24 and Abigail's age is 32
Answer:68.2
Step-by-step explanation:
cos6=71/EF
cos6= 0.960170286650366
0.960170286650366= 71/EF
0.960170286650366*71=EF
EF= 68.2
<span>Table:
Class Boundaries Frequency
5-10 8
10-15 9
15-20 15
20-25 10
25-30 8
30-35 6
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total 56
Average =
[5+10]/2*8+[10+15]/2*9+[15+20]/2*15+[20+25]/2*10+[25+30]/2*8+[30+35]/2*6
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</span> 56
That is 1075 / 56 = 19.2
Answer: 19
Answer:
The distribution is skewed, so use the five-number summary. range: 38, median: 16, half of the data are between 9.5 and 25
Step-by-step explanation:
In the picture attached the histogram is shown. We can see that data is skewed to the right, so we have to use the five-number summary. The range of the data is 39 - 1 = 38 (subtraction of the maximum value to the minimum value); the median is (15 + 17)/2 = 16 (if you order the values, 15 and 17 are in the middle); quartile 1 is 9.25 and quartile 3 is 25.5 (see diagram of box and whisker attached), then half of the data are between those values.
Answer:
Range - {-4,0,12,20}
Step-by-step explanation:
Given that,
The function is :
g(x) = 4x –12
The domain of the function is {2, 3, 6, 8}.
g(2) = 4(2) –12 = -4
g(3) = 4(3) –12 = 0
g(6) = 4(6) –12 = 12
g(8) = 4(8) –12 = 20
Hence, the range of the function is {-4,0,12,20}.
