Answer:
Step-by-step explanation:
Let the solution to
2x^2 + x -1 =0
x^2+ (1/2)x -(1/2)
are a and b
Hence a + b = -(1/2) ( minus the coefficient of x )
ab = -1/2 (the constant)
A. We want to have an equation where the roots are a +5 and b+5.
Therefore the sum of the roots is (a+5) + (b+5) = a+ b +10 =(-1/2) + 10 =19/2.
The product is (a+5)(b+5) =ab + 5(a+b) + 25 = (-1/2) + 5(-1/2) + 25 = 22.
So the equation is
x^2-(19/2)x + 22 =0
2x^2-19x + 44 =0
B. We want the roots to be 3a and 3b.
Hence (3a) + (3b) = 3(a+b) = 3(-1/2) =-3/2 and
(3a)(3b) = 9(ab) =9(-1/2)=-9/2.
So the equation is
x^2 +(3/2) x -9/2 = 0
2x^2 + 3x -9 =0.
Answer:
The zeroes are at (-2, 0), (0, 0) and (2, 0).
The (0, 0) is a double root as the graph just touches the x axis at (0, 0).
The zero at (0, 0) is sometimes referred as x = 0 (multiplicity 2).
I think the duplicate roots are counted as 2 distinct roots but im not sure.
So the answer is either a or c.
Step-by-step explanation:
The zeroes are the points where the graph cuts the x axis.
Your answer is 0, use PEMDAS and left to right 1+1=2 then subtract your 2, so 2-2=0
Answer:
$41.50 profit
Step-by-step explanation:
First, 1.25x48=60
Second, 60-18.50=41.50
Answer:
0.09259259
Step-by-step explanation:
