The surface area of triangular prism is 117.12 mm²
<u>Explanation:</u>
Base side, a = 9 mm
Base side, b = 6.6 mm
Base side, c = 5.2 mm
Height, h = 4 mm
Total surface area = ?
We know,
Surface area, A = 2 Ab ( a+b+c) h
Ab = √s(s-a) (s-b) (s-c)
s = a+b+c/2
Solving for A
A = ah + b h + ch + 1/2 √ -a⁴ + 2(ab)² + 2(ac)² - b⁴ + 2 (b c)² - c⁴
A = 9.4 + 6.6 X 4 + 5.2 X 4 + 1//2 √ -9⁴ + 2(9 X 6.6)² + 2(9 X 5.2)² - (6.6)⁴ + 2 (6.6 X 5.2)² - (5.2)⁴
A = 117.12 mm²
Therefore, the surface area of triangular prism is 117.12 mm²
Answer:
y=3x+7
Step-by-step explanation:
cause bla bla bla and bing bong bang thats how
40.75 - 7.05= 33.7
33.7 / 2 = 16.85
16.85 ft. should be on each side of the 7.05 ft. bench
Perimeter of a square = 4s
Required perimeter =
Answer: Center (0, -8) and Radius = 2
The standard equation of a circle is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius.
You can write the equation as (x-0)² + (y-( -8))² = 2². From this, you can conclude that the center is (0,-8) and the radius is 2.
