For combustion reaction we need oxygen and the results most of the time produce heat which mean first one is correct.
Answer:
mass of CO2 = 88 g
Explanation:
It is stated in question that 18.7 g of oxygen remained unreacted which means that carbon is limiting reactant. Thus the amount of carbon dioxide produced depend upon the amount of carbon.
Given data:
mass of carbon = 24 g
total mass of oxygen 82.7 g
mass of unreacted oxygen = 18.7 g
mass of carbon dioxide = ?
Solution:
First of we will calculate the moles of carbon.
number of moles of carbon = mass of carbon / atomic weight
number of moles of carbon = 24 g/ 12 g/mol = 2 mol
Chemical equation:
C + O2 → CO2
now we compare the number of moles of carbon and carbon dioxide,
C : CO2
1 : 1
2 : 2
Now we will calculate the mass of carbon dioxide from moles.
number of moles of CO2 = mass of CO2 / molar mass of CO2
2 mol × 44 g/mol = mass
mass of CO2 = 88 g
Answer
(a)
Extracellular= 0.230 osmols
Intracellular=0.270 osmols
(b)
As concentration of intracellular fluid is higher than extracellular fluid,solvent enters into the cell until the concentration inside and outside are Equal during this,the cell will become swallow.
Check attachment for calculation
Answer:
Determining the Slope on a p-t Graph. It was learned earlier in Lesson 3 that the slope of the line on a position versus time graph is equal to the velocity of the object. ... If the object has a velocity of 0 m/s, then the slope of the line will be 0 m/s. The slope of the line on a position versus time graph tells it all.
Explanation:
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