Answer:
Solid metal
Explanation:
The reduced form of metal ions is the metal in elemental state (simple substance). So, if you have a solution with metal ions and they are reduced, you probably will see the deposition of the metal. For example: if you have a solution with sodium ions (Na⁺), and the ions are then reduced, you will see the aparition of a solid phase of metallic sodium (Na(s)), according to the following half-reaction:
Na⁺ + e- → Na(s)
Answer:
The conversion achieved for the first CSTR impeller is 0.382
Discrepancy = 0.188
Explanation:
The impeller divides the CSTR into 2 equal reactors of volume 500gal
Using V = FaoX/ (-ra)
500gal = Fao×Xa/[(KCao^2( 1 -X1)^2]
500gal = CaoVoX1/ KCao^2(1-X1)
500gal= 500gal × X1'/(1 - X1)^2
(1 -X1)^2 = X1
X1^2 - 3X1 + 1 = 0
X1= 0.382
Conversion achieved in the first CSTR is 0.382
Actual measured CSTR = 57% =57/100=0.57
Discrepancy in the conversions= 0.57 -0.383 =0.188
Compounds Na₂SO₄ and NaCl are mixed together are we are asked to find the concentration of Na⁺ in the mixture
Na₂SO₄ ---> 2 Na⁺ + SO₄³⁻
1 mol of Na₂SO₄ gives out 2 mol of Na⁺ ions
the number of Na₂SO₄ moles added - 0.800 M/1000 * 100 ml
= 0.08 mol
therefore number of Na⁺ ions from Na₂SO₄ = 0.08 * 2 = 0.16 mol
NaCl ----> Na⁺ + Cl⁻
1 mol of NaCl gives 1 mol of Na⁺ ions
number of NaCl moles added = 1.20 M/1000 * 200 ml
= 0.24 mol
number of Na⁺ ions from NaCl = 0.24 mol
total number of Na⁺ ions in the mixture = 0.16 mol + 0.24 mol = 0.4 mol
as stated the volumes are additive,
therefore total volume = 100 ml + 200 ml = 300 ml
the concentration of Na⁺ ions = number of moles / volume
= 0.4 mol/ 0.3 dm³
concentration of Na⁺ = 1.33 mol/dm³
Answer:
C. Tip had the lower pressure, it was 652.71mmHg
Explanation:
To answer this question you need to convert both values into a common unit so you can compare directly.
87kPa = 652.71 mmHg
Answer:
I believe it is B
Explanation:
hope it helps. please let me know if it's wrong
