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zvonat [6]
3 years ago
5

How many moles of AgCl2 are in 5.78x1024 molecules of AgCl2?

Chemistry
1 answer:
Zolol [24]3 years ago
3 0

Answer:

9.6 mol AgCl2

Explanation:

You have to use Avogadro's number: 6.023 x 10^23

5.78 x 10^24 molecules (1 mol AgCl2/ 6.023 x 10^23 molecules) =9.6 mol AgCl2

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In an isolated system:
ipn [44]

Answer:

isolated system (plural isolated systems) (physics) A system that does not interact with its surroundings. Depending on context this may mean that its total energy and/or momentum stay constant.

Explanation:

An isolated system is a thermodynamic system that cannot exchange either energy or matter outside the boundaries of the system. ... The system may be enclosed such that neither energy nor mass may enter or exit.

is there both?

7 0
3 years ago
How many moles of copper are needed to react with sulfur to produce 0.25 moles of copper sulfide
Setler [38]
                                        Cu + S ---> CuS
by reaction                      1 mol           1 mol
from the problem         0.25 mol        0.25 mol
 0.25 mol   Cu
6 0
3 years ago
Read 2 more answers
Which of the following elements would form the smallest ionic radius and why?
AnnyKZ [126]

Answer:

Sodium

Explanation:

5 0
2 years ago
67.4 L of sulfur dioxide (SO2) gas at 0.0C and at 1 atm of pressure is equivalent aren’t to how many moles?
gizmo_the_mogwai [7]

Solution here,

Volume(V)=67.4 L

Pressure(P)=1 atm

Temperature(T)=(0+273)K=273K

Universal gas constant(R)=0.0821 L.atm.mol^-1K^-1

No. of moles(n)=?

Now,

PV=nRT

or, 1×67.4=n×0.0821×273

or, 67.4=22.4n

or, n=67.4/22.4

or, n=3

therefore, required no. of mole is 3.

6 0
3 years ago
A 25.0-mL sample of 0.150 M hydrocyanic acid is titrated with a 0.150 M NaOH solution. The Ka of hydrocyanic acid is 4.9 × 10-10
lara [203]

Answer:

The pOH = 1.83

Explanation:

Step 1: Data given

volume of the sample = 25.0 mL

Molarity of hydrocyanic acid = 0.150 M

Molarity of NaOH = 0.150 M

Ka of hydrocyanic acid = 4.9 * 10^-10

Step 2: The balanced equation

HCN + NaOH → NaCN + H2O

Step 3: Calculate the number of moles hydrocyanic acid (HCN)

Moles HCN = molarity * volume

Moles HCN = 0.150 M * 0.0250 L

Moles HCN = 0.00375 moles

Step 3: Calculate moles NaOH

Moles NaOH = 0.150 M * 0.0305 L

Moles NaOH = 0.004575 moles

Step 4: Calculate the limiting reactant

0.00375 moles HCN will react with 0.004575 moles NaOH

HCN is the limiting reactant. It will completely be reacted. There will react 0.00375 moles NaOH. There will remain 0.004575 - 0.00375 = 0.000825 moles NaOH

Step 5: Calculate molarity of NaOH

Molarity NaOH = moles NaOH / volume

Molarity NaOH = 0.000825 moles / 0.0555 L

Molarity NaOH = 0.0149 M

Step 6: Calculate pOH

pOH = -log [OH-]

pOH = -log (0.0149)

pOH = 1.83

The pOH = 1.83

6 0
3 years ago
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