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Tju [1.3M]
3 years ago
9

QUESTIONS

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
3 0

Answer:

B.

Explanation:

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Its D. Because the rest of the mass turned to gas
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Use dimensional analysis to solve the following problems. Pay attention to correct use of units and correct use of significant f
umka21 [38]

Answer:

1) 0.00498 mol Cu.

2) 0.00000374 mol CO₂

Explanation:

Question 1)

We want to convert 3.00 * 10²¹ copper atoms into moles. Note that 3.00 is three significant figures.

Recall that by definition, one mole of a substance has exactly 6.022 * 10²³ amount of that substance. In other words, we have the ratio:

\displaystyle \frac{1\text{ mol}}{6.022\times 10^{23} \text{ Cu}}

We are given 3.00 * 10²¹ Cu. To cancel out the Cu, we can multiply it by our above ratio with Cu in the denominator. Hence:

\displaystyle 3.00 \times 10^{21} \text{ Cu} \cdot \frac{1\text{ mol Cu}}{6.022\times 10^{23} \text{ Cu}}

Cancel like terms:

=\displaystyle 3\times 10^{21} \cdot \frac{1\text{ mol Cu}}{6.022\times 10^{23} }

Simplify:

\displaystyle  = \frac{3\text{ mol Cu}}{6.022 \times 10^{2}}

Use a calculator:

= 0.004981... \text{ mol Cu}

Since the resulting answer must have three significant figures:

= 0.00498\text{ mol Cu}

So, 3.00 * 10²¹ copper atoms is equivalent to approximately 0.00498 moles of copper.

Question 2)

We want to convert 2.25 * 10¹⁸ molecules of carbon dioxide into moles. Note that 2.25 is three significant digits.

By definition, there will be 6.022 * 10²³ carbon dioxide molecules in one mole of carbon dioxide. Hence:

\displaystyle \frac{6.022 \times 10^{23} \text{ CO$_2$}}{1\text{ mol CO$_2$}}

To cancel the carbon dioxide from 2.25 * 10¹⁸, we can multiply it by the above ratio with the carbon dioxide in the denominator. Hence:

\displaystyle 2.25\times 10^{18} \text{ CO$_2$} \cdot \frac{1\text{ mol CO$_2$}}{6.022\times 10^{23} \text{ CO$_2$}}

Cancel like terms:

\displaystyle= 2.25\times 10^{18} \cdot \frac{1\text{ mol CO$_2$}}{6.022\times 10^{23}}

Simplify:

\displaystyle = \frac{2.25 \text{ mol CO$_2$}}{6.022\times 10^5}}

Use a calculator:

=0.000003736...\text{ mol CO$_2$}

Since the resulting answer must have three significant figures:

= 0.00000374\text{ mol CO$_2$}

So, 2.25 * 10¹⁸ molecules of carbon dioxide is equivalent to approximately 0.00000374 moles of carbon dioxide.

4 0
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Sulfuric acid is a polyprotic acid. Write balanced chemical equations for the sequence of reactions that sulfuric acid can under
Dmitriy789 [7]

Answer:

H₂SO₄ (aq) + H₂O (l)  → HSO₄⁻ (aq) + H₃O⁺ (aq)

HSO₄⁻ (aq) + H₂O (l) ⇄  SO₄⁻²(aq) + H₃O⁺ (aq)           Ka

Explanation:

The sulfuric acid is a dyprotic acid.

It is a considered a strong acid but only the first deprotonation is strong.

Second deprotonation is totally weak

That's why we have equilibrium when it release the second proton.

Since a deprotonation is treated for a weak acid, the acid is considered not to completely dissociate, that's why the equilibrium

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What's a trend in electron affinity?
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Electron affinity is the change in energy of an atom with a neutral charge when an electron is added to form an anion. A more negative electron affinity corresponds to a greater attraction for an electron. Electron affinity become less negative down a group and from left to right in the periodic table.


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Why do the two electrons spend their time equally between both hydrogen atoms? In other words, why can’t one hydrogen just take
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Because it is a covalent bond meaning that they share the electrons to achieve full valence.
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