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alexdok [17]
3 years ago
5

Quadrilateral abcd is inscribed in a circle with m∠a = (x)degrees, m∠b = (2x - 10)degrees, and m∠c = (3x)degree. what is m∠d?

Mathematics
1 answer:
Lynna [10]3 years ago
6 0
Hello,

When you have a polygon inscribed in a circle, the opposite angles are supplementary.

So we can start by saying that A + C = 180. Or x + 3x = 180. This gives us a value of 45 for x.

If we input that in for angle B, we get: 2(25) - 10 = 80.

If angle B = 80, then angle D must be 100, because the angles are supplementary.

Good luck,
MrEQ
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\large\bf{\underline{Given :}}

  • An isosceles triangle ABC
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__________________________________________

\large\bf{\underline{To \:prove :}}

  • BD = DC

__________________________________________

\large\bf{\underline{In \: triangle \: ABD\:and\: triangle\:ADC}}

{⟹AD = AD\:\:\:\:\:\:\:\:\:\:\:\:\:\:( common)}

{⟹∠BAD = ∠CAD\:\:\:\:\:\:\:\:\:( given : AD \:is \:bisector \:of \:∠A )}

{⟹∠ABD = ∠ACD\:\:\:\:\:\:\:\:\:( given : angles\: in \:isosceles\: trianlge )}

\large\bf{\underline{Hence}}

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\large\bf{\underline{So}}

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\large\bf{BD = DC}

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\large\bf{\underline{Note :}}Slide to view full answer.

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3 years ago
You can read 52 pages per hour.
lidiya [134]

Answer:

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Crank

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