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seropon [69]
3 years ago
11

A Ford is traveling 20 mph slower than a Buick. The Buick is traveling at a rate of 65 mph. Let F = the the speed of the Ford. W

hich formula below would correctly calculate the speed of the Ford?
Mathematics
1 answer:
snow_tiger [21]3 years ago
8 0
Answer: The formula to find the speed of the Ford could be F = B - 20.

Since the Ford is 20 mph slower than the Buick, all you have to do is subtract 20 from the speed of the Buick. We know the speed of the Buick, it is 65.

Therefore, the speed of the Buick is 65 - 20 or 45 mph.
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Which classification best describes the following system of equations? 3x+6y-12z=36 x=2y-4z=12 4x+8y-16z=48 inconsistent and dep
Viktor [21]

<u>Answer:</u>

Consistent and dependent

<u>Step-by-step explanation:</u>

We are given the following equation:

1. 3x+6y-12z=36

2. x+2y-4z=12

3. 4x+8y-16z=48

For equation 1 and 3, if we take out the common factor (3 and 4 respectively) out of it then we are left with x+2y-4z=12 which is the same as the equation number 2.

There is at least one set of the values for the unknowns that satisfies every equation in the system and since there is one solution for each of these equations, this system of equations is consistent and dependent.

6 0
3 years ago
Merit works in a florist shop and makes flower arrangements
Vikentia [17]
So what is the question
5 0
3 years ago
What is the measure of angle c? (Brainliest and Bonus points for best answer)
k0ka [10]

Answer:

\displaystyle 65°

Step-by-step explanation:

Angle <em>b</em> and 135° form a <em>linear pair</em>, so when summing them up to 180°, you will have 45° left over:

\displaystyle 180° = 135° + m∠b; 45° = m∠b

Now, by the <em>Vertical</em><em> </em><em>Angles</em><em> </em><em>Theorem</em>, angle <em>a</em> and 70°, in this case, are to be in <u>congruence</u> with each other, so you have that.

Now you must find the the measure of angle <em>c</em> sinse you have already found the measure of two angles already:

\displaystyle 180° = 45° + m∠c + 70° → 180° = 115° + m∠c; 65° = m∠c

I am joyous to assist you at any time.

3 0
3 years ago
Read 2 more answers
Giselle pays $210 in advance on her account at the athletic club. Each time she uses the club, $15 is deducted from the account.
weqwewe [10]

Answer:

A.b = 210 + 15x

B.b = 210 – 15x

C.b = 195 + 15x

D.b = 195 – 15x

Step-by-step explanation

B is correct. Your starting amount is 210$ And you're taking away 15$ each time she uses the club,x.

3 0
3 years ago
Simplify the expression below and write it as a single logarithm:
OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

<u>Solution:</u>

Given, expression is 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)

Rearranging the terms we get,

\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)

\text { since a } \times \log b=\log \left(b^{a}\right)

\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)

\text { We know that } \log a \times \log b=\log a b

\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.

\text { We know that } \log a-\log b=\log \frac{a}{b}

\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

Hence, the simplified form \rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)

4 0
3 years ago
Read 2 more answers
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