Given:
Two similar rectangles.
To find:
The area of the larger rectangle.
Solution:
Let x be the other side of the larger rectangle.
Corresponding sides of similar figures are always congruent.
![\dfrac{x}{1}=\dfrac{4}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%7D%7B1%7D%3D%5Cdfrac%7B4%7D%7B2%7D)
![x=2](https://tex.z-dn.net/?f=x%3D2)
The other side of larger rectangle is 2 cm.
We know that, area of rectangle is
![Area=Length\times Width](https://tex.z-dn.net/?f=Area%3DLength%5Ctimes%20Width)
So, area of the larger rectangle is
![Area=4\times 2](https://tex.z-dn.net/?f=Area%3D4%5Ctimes%202)
![Area=8](https://tex.z-dn.net/?f=Area%3D8)
Therefore, the area of the larger rectangle is 8 sq. cm.