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Artemon [7]
3 years ago
8

What is the nearest thousand, hundreds, tens for 7931

Mathematics
1 answer:
photoshop1234 [79]3 years ago
3 0
To the nearest thousand, it is 8,000
To the nearest hundred, it is 7,900
To the nearest ten, it is 7,930

Hope that helped :)
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Solve for w 4w - 9 = 7
bagirrra123 [75]

Answer:

w = 4

Step-by-step explanation:

1. Isolate the variable by adding 9 to both sides

--> 4w = 16

2. Divide each side by 4

--> w = 4

-If this answer helps you, please remember to vote it as 'brainliest answer' :)

Thank you!

6 0
3 years ago
Marking the first 2 people brainliest if they answer
Vikki [24]

Answer:

the answer is the one you have selected

Step-by-step explanation:

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2(vh)/k=r Solve equation for v in terms of all other variables involved
aivan3 [116]

The equation v in terms of other variables is v = kr/2h

<h3>What is the subject of an equation?</h3>

It is a variable which is expressed in terms of other variables involved in the formula.

Formulas are written so that a single variable, the subject of the formula is on the L.H.S. of the equation. Everything else goes on the right side of the equation. We evaluate the formula by substituting for the literal numbers on the right hand side.

2(vh) / k = r

by cross multiplication

2(vh) = kr

divide both sides by 2h

v = kr/2h

In conclusion, v in terms of other variables is  kr/2h

Learn more about subject of an equation: brainly.com/question/657646

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6 0
1 year ago
What comes after ones column?
alekssr [168]

Answer: tens

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7 0
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Read 2 more answers
Sin0=12/37 find tan0
alexira [117]

Answer:

\large{ \tt{❃ \: EXPLANATION}} :

  • We're provide - Sin θ = \frac{12}{37} which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ = \tt{  \frac{p}{h}} ] . We're asked to find out tan θ ].

\large{ \tt{❁ \: USING \: PYTHAGORAS \: THEOREM}} :

\large{ \tt{❊ \:  {h}^{2}  =  {p}^{2}  +  {b}^{2} }}

\large{ \tt{⇢ {p}^{2} +  {b}^{2}   =  {h}^{2} }}

\large{ \tt{⇢ \:  {b}^{2}  =  {h}^{2}  -  {p}^{2} }}

\large{ \tt{⇢ \:  {b}^{2} = {37}^{2} -  {12}^{2}   }}

\large{ \tt{⇢ \:  {b}^{2}  = 1369 - 144}}

\large{ \tt{ ⇢{b}^{2}  = 1225}}

\large{ \tt{⇢ \: b =  \sqrt{1225}}}

\large{ \tt{⇢ \: b = 35  \: \text {units}}}

  • Now , We know - Tan θ= \tt{ \frac{perpendicular}{base} }. Just plug the values :

\large{ \tt{➝ \: Tan  \: \theta =  \frac{p}{b}  = \boxed{ \tt{  \frac{12}{35} }}}}

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

5 0
3 years ago
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