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ratelena [41]
3 years ago
8

Can someone help me? It's urgent and thank you!

Mathematics
1 answer:
nordsb [41]3 years ago
3 0

Answer:

the first one

Step-by-step explanation:

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The electrical resistance of aire is directly proportional to its length. If a 45-foot long wire has a resistance of 9 ohm(s), f
wolverine [178]
The resistance is proportional to the length.
You know that 45/9=5
So the ratio (proportionality) is 5.
So, for a 75 ft wire, the resistance is 75/5 = 15 ohms
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3 years ago
Yuri has a rope 12m long. he cuts it into pieces that are each 2m long. what fraction of the rope is one piece
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Yuri will have 6 pieces because 12 divided by 2 is 6.


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4 years ago
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To help with her retirement savings, Donna has decided to invest. Assuming an interest rate of 3.59% compounded quarterly, how m
cricket20 [7]

Answer:

We get the value of Principal amount i.e initial investment = $61640

Step-by-step explanation:

Interest rate r = 3.59% or 0.0359

Compounded quarterly n = 4

Future Amount A = 117,300

Time t = 18 years

We need to find initial investment i,e Principal Amount P

The formula used is: A=P(1+\frac{r}{n})^{nt}

Putting values and finding P

A=P(1+\frac{r}{n})^{nt}\\117300=P(1+\frac{0.0359}{4})^{4*18} \\117300=P(1+0.008975)^{72}\\117300=P(1.008975)^{72}\\117300=P(1.903)\\P=\frac{117300}{1.903}\\P=61640

So, We get the value of Principal amount i.e initial investment = $61640

7 0
3 years ago
A rocket carrying fireworks is launched from a hill 60 feet above a lake. The rocket will fall into the lake after exploding at
castortr0y [4]

Answer:

<h3>A) 204m</h3><h3>B) 188m</h3>

Step-by-step explanation:

Given the rocket's height above the surface of the lake given by the function h(t) = -16t^2 + 96t + 60

The velocity of the rocket at its maximum height is zero

v = dh/dt = -32t + 96t

At the maximum height, v  = 0

0 = -32t + 96t

32t = 96

t = 96/32

t = 3secs

Substitute t = 3 into the modeled function to get the maximum height

h(3) = -16(3)^2 + 96(3) + 60

h(3) = -16(9)+ 288 + 60

h(3) = -144+ 288 + 60

h(3) = 144 + 60

h(3) = 204

Hence the maximum height reached by the rocket is 204m

Get the height after 2 secs

h(t) = -16t^2 + 96t + 60

when t = 2

h(2) = -16(2)^2 + 96(2) + 60

h(2) = -64+ 192+ 60

h(2) = -4 + 192

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Hence the height of the rocket after 2 secs is 188m

3 0
3 years ago
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If you can give me more information on this I could help you a bit more respond.
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2 years ago
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