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Brums [2.3K]
4 years ago
15

Which points on the graph represent values that could

Mathematics
2 answers:
AlladinOne [14]4 years ago
8 0

Answer:

D and B

Step-by-step explanation:

bulgar [2K]4 years ago
3 0
It would be A and D! hope this helps
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A,B and C are the vertices of a triangle A has coordinates (4,6) B has coordinates (2,-2) C has coordinates (-2,-4) D is the mid
polet [3.4K]

Answer:

Segments DE and BC have equal slopes, showing that segments DE and BC are parallel

Step-by-step explanation:

Here we have the coordinates as follows

The coordinates of A is (4, 6)

The coordinates of B is (2, -2)

The coordinates of C is (-2, -4)

Therefore, the coordinates of D the midpoint AB is ((4 + 2)/2, (6 - 2)/2) which gives;

The coordinates of D is (3, 2)

Similarly, the coordinates of E the midpoint AC is ((4 - 2)/2, (6 - 4)/2) which gives;

The coordinates of E is (1, 1)

To prove that segment DE is parallel to segment BC, e show that the slopes of the two segments are equal as follows;

Slope \, of \, a \, segment = \frac{Change \, in \, the\ y \, coordinates}{Change \, in \, the\, x \, coordinates}

Slope \, of \, segment \  DE =\frac{2 - 1}{3-1} = \frac{1}{2}

Slope \, of \, segment \  BC =\frac{-2 - (-4)}{2-(-2)} = \frac{2}{4} =\frac{1}{2}

Therefore, the slopes of segments DE and BC are equal, which shows that segment DE is parallel to BC.

8 0
4 years ago
Credit unions are not subject to federal regulations. A. True B. False
Stolb23 [73]

Answer:

The correct answer is (FALSE)

Step-by-step explanation:

(APEX)

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3 years ago
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Answer:

f 852

Step-by-step explanation:

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3 years ago
According to the Population Reference Bureau (www.prb.org), the Ukraine's annual growth rate during the next 40 years is project
Anettt [7]

Here's link to the answer:

tinyurl.com/wtjfavyw

5 0
3 years ago
Read 2 more answers
Help I’ll do anything just help
Gnom [1K]

Answer:

1) {n}^{2}  - 81 \\ (n - 9)(n + 9)

2) \:  \: {a}^{2}  - 121 \\ (a - 11)(a + 11)

3) \:  \:  {n}^{2}  - 16 \\ (n - 4)(n + 4)

4)  \:  \: 9 {x}^{2}  - 144 \\  {3}^{2}  {x}^{2}  -  {12}^{2}  \\ (3x - 12)(3x + 12)

5) \: 2 {x}^{2}  - 9 \\ (2x - 3)(x + 3)

6) \:  \: 4 {w}^{2}  - 9 \\  {2}^{2}  {w}^{2}  -  {3}^{2}  \\ (2w + 3)(2w - 3)

7) \:  \: 4 {n}^{2}  - 1 \\  {2}^{2}  {n}^{2}  -  {1}^{2}  \\ (2n  + 1)(2n - 1)

8) \:  \: 1 - 16 {x}^{2}  \\  {1}^{2}  -  {4}^{2}  {x}^{2}  \\ (1 - 4x)(1  +  4x)

9) \:  \: {x}^{2}   - {y}^{2}  \\ (x - y)(x + y)

10) \:  \: 9 -  {c}^{2}  \\  {3}^{2}  -  {c}^{2}  \\ (3 - c)(3 + c)

11) \:  \:  {n}^{2} -  25 \\  {n}^{2}  -  {5}^{2}  \\ (n + 5)(n - 5)

13)49 - 4 {a}^{2}  \\  {7}^{2}  -  {2}^{2}  {a}^{2}  \\ (7 - 2a)(7 + 2a)

14) {a}^{2}  {b}^{2}  -  {c}^{4}  \\ (ab -  {c}^{2} )(ab +  {c}^{2} )

15) \:  \: 4  {x}^{2}  {y}^{2}  - 9 {z}^{2} \\  {2}^{2}   {x}^{2}  {y}^{2}  -  {3}^{2}  {z}^{2}  \\ (2xy - 3z)(2xy + 3z)

hope this helps

sorry, I don't know how solve the 12th one.

thanks.

7 0
3 years ago
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