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olga nikolaevna [1]
3 years ago
5

Can some one help me figure out how to do problems 30-41

Mathematics
1 answer:
madreJ [45]3 years ago
4 0
Give me a minute or two to graph them and then ill let you know :)
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A door delivery florist wishes to estimate the proportion of people in his city that will purchase his flowers. Suppose the true
zloy xaker [14]

Answer:

The probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.009.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

As the sample size is large, i.e. <em>n</em> = 492 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportion by the normal distribution.

The mean and standard deviation of the sampling distribution of sample proportion are:

\mu_{\hat p}=p=0.07\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.07(1-0.07)}{492}}=0.012

Compute the probability that the sample proportion will differ from the population proportion by greater than 0.03 as follows:

P(|\hat p-p|>0.03)=P(|\frac{\hat p-p}{\sigma_{\hat p}}|>\frac{0.03}{0.012})

                           =P(|Z|>2.61)\\\\=1-P(|Z|\leq 2.61)\\\\=1-P(-2.61\leq Z\leq 2.61)\\\\=1-[P(Z\leq 2.61)-P(Z\leq -2.61)]\\\\=1-0.9955+0.0045\\\\=0.0090

Thus, the probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.009.

5 0
3 years ago
Hi what is the answerr??
inna [77]

Given:

The rule of input and output function is:

25-g

To find:

The answer if we put 19.

Solution:

Consider the input and output function is:

f(g)=25-g

Substitute g=19, we get

f(19)=25-19

f(19)=6

Therefore, the required answer is 6.

7 0
3 years ago
September 6 is a Read Book Day.Polina read 5 times as many pages as Marcus read.Together,the read 108 pages.How many pages did e
Gemiola [76]

Answer:

The number of pages that Polina read was 90 and the number of pages that Marcus read was 18

Step-by-step explanation:

Let

x -----> number of pages that Polina read

y ----> number of pages that Marcus read

we know that

x+y=108 ----> equation A

x=5y -----> equation B

substitute equation B in equation A and solve for y

5y+y=108\\6y=108\\y=18

Find the value of x

x=5y -----> x=5(18)=90

therefore

The number of pages that Polina read was 90 and the number of pages that Marcus read was 18

3 0
3 years ago
A box is in the shape of an equilateral triangular prism. if the box is to be covered with paper on its lateral sides, how many
Zarrin [17]

The total surface area of the triangular prism that has a height of h and the side length of a is given below.

\rm a(\dfrac{\sqrt3}{2} \ a + 3h)

<h3>What is a triangular prism?</h3>

A triangular prism is a closed solid that has two parallel triangular bases connected by a rectangle surface.

A box is in the shape of an equilateral triangular prism.

If the box is to be covered with paper on its lateral sides.

Let a be the side length of the equilateral triangle and h be the height of the prism.

Then the surface area of the triangular prism will be

Surface area = 2 × area of triangle + 3 × area of the rectangle

The area of the triangle will be

\rm Area\ of\ triangle = \dfrac{\sqrt{3}a^2}{4}

The area of the rectangle will be

\rm Area \ of \ rectangle = a \ h

Then the total surface area will be

\rm Surface\ area =  2 \times \dfrac{\sqrt3 a^2 }{4} + 3 ah\\\\\\Surface\ area =  a(\dfrac{\sqrt3}{2} \ a + 3h)

More about the triangular prism link is given below.

brainly.com/question/21308574

7 0
2 years ago
Ryan buys some jumpers to sell on a stall.
katovenus [111]

Answer:

£540

Step-by-step explanation:

I worked it out let me know if you want me to upload a picture of my workings

8 0
3 years ago
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