Answer:
Step-by-step explanation:
Bob ran the first part of a 12 km race at a speed of 8 kmph. He ran the second part of the
race at 10 kmph. If his total time for the entire race was 1.74 hours, how far did he run in
the first part of the race?
First part :
Total Distance = 12 km
First part Speed = 8kmph
Let distance covered on first part = x
Second part speed = 10kmhr
(8*x)
Answer:
2x²y+(x²y-2xy²) = 3x²y-2xy²
(5xy²-x²y) +3x²y = 5xy²-2x²y
4x²y+(x²y+xy²) = 5x²y+xy²
x²y+(-2xy²-4x²y) = -3x²y-2xy²
Step-by-step explanation: there you go
Answer:
Do you mean solve for t?
If you do, the answer is 9.
Step-by-step explanation:
If we expand the equation out, we get:
-t = 9t - 90
If we move the -90 over to the left side and the -t to the right side, we get:
90 = 10t
Dividing both sides by 9, we get:
t = 9
If the relationship between two quantities is a proportional relationship, this relationship can be represented by the graph of a straight line through the origin with a slope equal to the unit rate. For each point (x, y) on the graph, ž is equal to k, where k is the unit rate. The point (1, k) is a point on the graph.
Answer:
(-3,6) (1,8) (2,10) and so on.
