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3 years ago

How to find the median from a frequency table

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

5 0

Answer:

To find the mean: Multiply midpoints by frequencies, add the subtotals and divide by the total of the frequencies.

Step-by-step explanation:

Put the results in numerical order (in a frequency table this will already be done)

Count the total amount of results and add one.

Divide this by 2 to find the the position of the middle result.

Find the middle result in the numerically ordered list or frequency table.

You might be interested in

Simplify the expression<br>a²+a+a²

sasho [114]

Answer:

2a^2+a

Step-by-step explanation:

you can simplify a^2 into itself twice

7 0

3 years ago

What is the y-coordinate of the solution for the system of equations?

8_murik_8 [283]

First equation is: x - y = 12
x = 12 + y

Now, substitute this in 2nd equation,
2x - 3y = 27
2(12+y) - 3y = 27
24 + 2y - 3y = 27
-y = 27 - 24
y = -3

In short, Your Answer would be -3

Hope this helps!

5 0

3 years ago

A new pop-up restaurant serving high-end street tacos just opened and is expected to have high demand based on the chef's prior

Harman [31]

Answer:

1. c

2. f

3. d

Step-by-step explanation:

This type of queuing model is an example of "single-channel, single-phase" process.

However, from the information given:

The inter-arrival rate = 10 customers per hour

Arrival time = 6 minutes

Service time = 5 minutes

∴

utilization = service time/arrival time

= 5/6

Time on queue $T_q = p \times \dfrac{utilization }{1 - utilization} \times \dfrac{Cv_a^2 -Cv_b^2}{2}$

$T_q = 5 \times \dfrac{5/6 }{1 -5/6} \times \dfrac{(2.58^2 -0.75^2)}{2}$

$T_q = 25 \times 3.60945$

$T_q = 90.24 \\ \\ T_q \simeq 90 \ mins$

Thus, customer waiting in the queue line is;

$= \dfrac{T_q}{q} \\ \\ = \dfrac{90}{6} \\ \\ \mathbf{=15}$

Thus, new customers will have to wait in a total time of;

= waiting time + service time

= 90 + 5

= 95 minutes.

4 0

3 years ago

If A = (0, 0) and B = (8, 2), what is the length of ? A. 9.41 units B. 8.25 units C. 3.16 units D. 7.75 units

Solnce55 [7]

The correct answer that you are looking for is B.

8 0

4 years ago

1. Suppose people ages 16-30 make up 15% of drivers on the road, 80% of drivers are aged 31-64, and 5% of drivers are aged 65+.

Yuliya22 [10]

Answer:

0.8675

Step-by-step explanation:

Given that people ages 16-30 make up 15% of drivers on the road, 80% of drivers are aged 31-64, and 5% of drivers are aged 65+.

Furthermore, suppose drivers in each age range cause car accidents at the rates of 6%, 4%, and 9%, respectively.

age 16-30 31-64 >65

Prob 0.15 0.8 0.05 1

Prob for accidents 0.06 0.09 0.04

Product 0.009 0.072 0.002 0.083

Prob for 31-64 causing it/accident = $\frac{0.072}{0.083} \\=0.8675$

Using Bayes theorem we got answer as 0.8675

3 0

4 years ago